Forum Discussion
Anonymous
4 years agoNot applicable
Finding Historical Data
Hi All, I have a dataset similar to the below. ID On Hire Date Off Hire Date 1 2 01/01/2021 30/01/2021 3 01/02/2021 4 01/03/2021 10/03/2021 5 01/04/2021 2...
- Anonymous4 years ago
Hi Anonymous ,
Please try:
On Hire based on today = CALCULATE(COUNTROWS('Table'),FILTER('Table',[On Hire Date]<>BLANK()&& [On Hire Date]<=TODAY() && [Off Hire Date]=BLANK()))If you want to calculate the count based on some selections, please firstly create a new calendar table with Dates for slicer
Calendar = CALENDAR(MIN('Table'[On Hire Date]), MAX('Table'[Off Hire Date]))On Hire at certain time = CALCULATE(COUNTROWS('Table'),FILTER('Table',[On Hire Date]<>BLANK()&& [On Hire Date]<=MAX('Calendar'[Date]) && ([Off Hire Date]=BLANK()|| [Off Hire Date]>=MAX('Calendar'[Date]))))On Hire over selected perioid = CALCULATE(COUNTROWS('Table'),FILTER('Table',[On Hire Date]<>BLANK() && [On Hire Date]<=MIN('Calendar'[Date]) && ( [Off Hire Date]>=MAX('Calendar'[Date]) || [Off Hire Date]=BLANK())))Best Regards,
Eyelyn Qin
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Anonymous
4 years agoNot applicable
Hi Anonymous ,
Please try:
On Hire based on today = CALCULATE(COUNTROWS('Table'),FILTER('Table',[On Hire Date]<>BLANK()&& [On Hire Date]<=TODAY() && [Off Hire Date]=BLANK()))
If you want to calculate the count based on some selections, please firstly create a new calendar table with Dates for slicer
Calendar = CALENDAR(MIN('Table'[On Hire Date]), MAX('Table'[Off Hire Date]))On Hire at certain time = CALCULATE(COUNTROWS('Table'),FILTER('Table',[On Hire Date]<>BLANK()&& [On Hire Date]<=MAX('Calendar'[Date]) && ([Off Hire Date]=BLANK()|| [Off Hire Date]>=MAX('Calendar'[Date]))))
On Hire over selected perioid = CALCULATE(COUNTROWS('Table'),FILTER('Table',[On Hire Date]<>BLANK() && [On Hire Date]<=MIN('Calendar'[Date]) && ( [Off Hire Date]>=MAX('Calendar'[Date]) || [Off Hire Date]=BLANK())))
Best Regards,
Eyelyn Qin
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.