Find middle date in between first and last date, and put in column

[Anonymous]

I have a table like this:

id	timestamp	temperature	first date - id	last date - id	middle date - id	first, last, middle
1	1/1/20 1:00 AM	14	TRUE	FALSE		First
1	1/1/20 2:00 PM	12.4	FALSE	FALSE		na
1	1/1/20 8:00 AM	16.3	FALSE	FALSE		na
1	1/2/20 1:00 AM	14.2	FALSE	FALSE		na
1	1/2/20 2:00 PM	15.9	FALSE	FALSE		na
1	1/2/20 8:00 AM	14.5	FALSE	FALSE		na
1	1/3/20 1:00 AM	13.2	FALSE	FALSE		na
1	1/3/20 2:00 PM	19.3	FALSE	TRUE		Last
1	1/3/20 8:00 AM	16.9	FALSE	FALSE		na
2	1/1/20 1:00 AM	14.3	TRUE	FALSE		First
2	1/1/20 2:00 PM	12.4	FALSE	FALSE		na
2	1/1/20 8:00 AM	16.3	FALSE	FALSE		na
2	1/2/20 1:00 AM	14.2	FALSE	FALSE		na
2	1/2/20 1:00 PM	15.9	FALSE	FALSE		na
2	1/2/20 8:00 AM	14.5	FALSE	FALSE		na
2	1/3/20 2:00 AM	13.2	FALSE	FALSE		na
2	1/3/20 1:00 PM	13.5	FALSE	TRUE		Last
2	1/3/20 8:00 AM	16.9	FALSE	FALSE		na

I have calculated the first and laste date using this formula: IF(tabledb[timestamp]=CALCULATE(MIN(tabledb[timestamp]),ALLEXCEPT('tabledb', 'tabledb'[id])),True)

How can I get the middle date in a format like last and first, and then create a new column to show first, middle and last date for every id, like shown in table above for first and last date.

Thanks a lot.

[Anonymous · Accepted solution]

@Anonymous 

I recommend you first ranked the timestamp for each id. Then use MEDIAN to get the middle rank for each id.

Rank= RANKX(FILTER(Tabledb,[id]=EARLIER(Tabledb[id])),Tabledb[timestamp],,ASC,Dense)

firstmidlast = 
IF(Tabledb[Rank]=MIN(Tabledb[Rank]),"first",IF(Tabledb[Rank]=MAX(Tabledb[Rank]),"last",IF(Tabledb[Rank]=MEDIAN(Tabledb[Rank]),"mid")))

Best,
Paul

[amitchandak]

create rank inside each id.  crease dense rank

refer -https://radacad.com/how-to-use-rankx-in-dax-part-2-of-3-calculated-measures

create rank as column.

Now using that you can use min and max of rank try to find middle rank and use that.

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