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I have a requirement to find whether a string given in Logon column contains a 'wauser' pattern ornot . If it contains the pattern it should return 1,if not 0.
I have data shown below
Qty | Logon | Tran_Date | Item_Nbr |
-100 | memwauser:MEM.MAIN | 9/17/2024 | 44675F|20 |
-100 | memwauser:MEM.MAIN | 10/15/2024 | 44152F|20 |
1,313 | cmurray:CBC.MAIN | 9/17/2024 | 43807|01 |
1,313 | joldenburg:CBC.MAIN | 9/17/2024 | 43807|01 |
Final Result should look like
Qty | Logon | Tran_Date | Item_Nbr | Usertype |
-100 | memwauser:MEM.MAIN | 9/17/2024 | 44675F|20 | 1 |
-100 | memwauser:MEM.MAIN | 10/15/2024 | 44152F|20 | 1 |
1,313 | cmurray:CBC.MAIN | 9/17/2024 | 43807|01 | 0 |
1,313 | joldenburg:CBC.MAIN | 9/17/2024 | 43807|01 | 0 |
Can you please let me know how this can be achieved using DAX in Power BI Desktop ?
Thanks..
Solved! Go to Solution.
Hi @csb,
You may want to add the following measure to get what you need:
UserType =
IF(CONTAINSSTRING(SELECTEDVALUE('Table'[Logon]), "memwauser"), 1, 0)
@csb
You can add calculated column as follows:
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Your solution is so great Fowmy and wini_R
Hi, @csb
I wish you all the best. Previously Super user and wini_R have provided a solution to help you solve the problem. Since we haven't heard back from you yet, I'd like to confirm if you've successfully resolved this issue or if you need further help?
If yes, you are welcome to share your workaround and mark it as a solution so that other users can benefit as well. If you find a reply particularly helpful to you, you can also mark it as a solution.
If you still have any questions or need more support, please feel free to let us know. We are more than happy to continue to help you.
Thank you for your patience and look forward to hearing from you.
Best Regards
Jianpeng Li
@csb
You can add calculated column as follows:
⭕ Subscribe and learn Power BI from these videos
⚪ Website ⚪ LinkedIn ⚪ PBI User Group
Hi @csb,
You may want to add the following measure to get what you need:
UserType =
IF(CONTAINSSTRING(SELECTEDVALUE('Table'[Logon]), "memwauser"), 1, 0)
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