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Hi everyone,
I want to find 2 and 3 consecutive rows where Index equals 1 and show the results as below.
Can you please help me. I'd like to use DAX, not power query as I can't go back to query at this step.
Thanks so much!
| Index | 2 consecutive rows (result) | 3 consecutive rows (result) |
| 1 | 1 | 0 |
| 1 | 1 | 0 |
| 0 | 0 | 0 |
| 1 | 1 | 1 |
| 1 | 1 | 1 |
| 1 | 1 | 1 |
| 0 | 0 | 0 |
| 1 | 0 | 0 |
| 0 | 0 | 0 |
| 1 | 1 | 1 |
| 1 | 1 | 1 |
| 1 | 1 | 1 |
Solved! Go to Solution.
You may add an index column in Query Editor and use DAX below to add a calculated column.
Column =
VAR c = 2
RETURN
IF (
Table1[Index] = 0
||
VAR i = Table1[Index.1]
VAR p =
MAXX (
FILTER ( Table1, Table1[Index.1] < i && Table1[Index] = 0 ),
Table1[Index.1]
)
VAR n =
MINX (
FILTER ( Table1, Table1[Index.1] > i && Table1[Index] = 0 ),
Table1[Index.1]
)
RETURN
IF ( ISBLANK ( n ), MAX ( Table1[Index.1] ) + 1, n )
- IF ( ISBLANK ( p ), MIN ( Table1[Index.1] ) - 1, p )
- 1
< c,
0,
1
)
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