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Hello everyone.
I have the following drawback.
I have a table that has a list of transactions. Transactions can be repeated X number of times. But I only need to count 1 record of that X amount if it meets other conditions.
For example, I have the transaction ZREC_VAR1. It is repeated twice. Additionally, these transactions have columns D and E and I need to count a record of those 2, only if they meet the condition of having "1" in column D and E.
In this case, of both records, my count should be 1.
What I need to do is count all the records that have "1" in columns D and E, but only once if they are repeated.
Solved! Go to Solution.
Hi @Syndicate_Admin ,
According to your description, here are my steps you can follow as a solution.
(1) This is my test data.
(2) We can create a measure.
Count =
var _table=DISTINCT('Table')
return COUNTROWS(FILTER(_table,[Transaccion R3]=MAX('Table'[Transaccion R3]) && [D column]=1 && [E column]=1))
(3) Then the result is as follows.
If the above one can't help you get the desired result, please provide some sample data in your tables (exclude sensitive data) with Text format and your expected result with backend logic and special examples. It is better if you can share a simplified pbix file. Thank you.
Best Regards,
Neeko Tang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @Syndicate_Admin ,
According to your description, here are my steps you can follow as a solution.
(1) This is my test data.
(2) We can create a measure.
Count =
var _table=DISTINCT('Table')
return COUNTROWS(FILTER(_table,[Transaccion R3]=MAX('Table'[Transaccion R3]) && [D column]=1 && [E column]=1))
(3) Then the result is as follows.
If the above one can't help you get the desired result, please provide some sample data in your tables (exclude sensitive data) with Text format and your expected result with backend logic and special examples. It is better if you can share a simplified pbix file. Thank you.
Best Regards,
Neeko Tang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.