Forum Discussion
Distinct count rows that are not blank!
- Anonymous9 years ago
=calculate( distinctcount(MyTable[MyColumn]), MyTable[MyColumn] <> BLANK())
=calculate( distinctcount(MyTable[MyColumn]), MyTable[MyColumn] <> BLANK())
- XMonsterX9 years ago
Advocate II
Good solution...
One issue.. It if you have duplicate values it counts it as one. For example, if my table column is what people chose as a favorite animal, it would have a lot of people choosing dogs. There would be for example 50 dogs, but this formula would count the 50 instances of "Dog" as one. (Just a simple example). If there's 50, you want the count to reflect that.
MeasureHappy = calculate(count(MyTable[MyColumn]), MyTable[MyColumn] <> BLANK())
Changing from distinctcount, to just plainly count will resolve this, for anyone not looking to count dups as a singular. (If you want a zero instead of null
MeasureHappy = calculate(count(MyTable[MyColumn]), MyTable[MyColumn] <> BLANK()) + 0
Happy Intellegence
David
- Anonymous9 years agoNot applicable
Thanks a lot!!! :)
- Anonymous9 years agoNot applicable
Hey Anonymous
If the distinctcount of a column is equal to zero then distinctcount returns BLANK(null). Can I fix this to show 0 instead of null?
- Oxenskiold9 years ago
Advocate I
Hi Anonymous,
you can use this:
=
CALCULATE ( DISTINCTCOUNT ( MyTable[MyColumn] ), MyTable[MyColumn] <> BLANK () ) + 0<Blank> + 0 equals 0
Kind regards
Oxenskiold
- Anonymous9 years agoNot applicable
Thanks Oxenskiold! :))
- fahadfarooqi9 years agoFrequent Visitor
- bajimmy19837 years ago
Advocate V
Excellent Anonymous. Thanks a lot!