Forum Discussion

Anonymous's avatar
Anonymous
Not applicable
6 years ago

Distinct count based on the another table column

I have two tables 'Table 1' and 'Table 2' both tables have column names ID.NR, Date, etc. these two tables are joined by IDNR, neither column contains unique values for column IDNR so the relation type is many to many and the cross filter direction is both.
I want to count distinct values of IDNR for Table 1, for the year 2018 if IDNR also exists in table 2. I tried to create a calculated column using the following formula but it didn't give me the right results.

Kolumn = CALCULATE(DISTINCTCOUNT(Table 1[IDNR]),FILTER(ALL(table 2)
,Table 2 [IDNR] = Table 1[IDNR] && Table 2[Year] = Table 1[Year]))

Data Protection
General Comment
Interesting Links
Need Help
Show and Tell
Tips and Tricks
Tutorial Requests

3 Replies

  • az38's avatar
    az38
    Community Champion
    6 years ago

    Hi Anonymous 

    try something like that

    = countrows(
distinct(
INTERSECT(
SELECTCOLUMNS(FILTER(ALL('Table 1');YEAR('Table 1'[Date]) =2018);"IDNR";[IDNR]);
SELECTCOLUMNS(FILTER(ALL('Table 2');YEAR('Table 2'[Date]) =2018);"IDNR";[IDNR])
)
)
)

    do not hesitate to give a kudo to useful posts and mark solutions as solution

     

    • Anonymous's avatar
      Anonymous
      Not applicable
      6 years ago

      az38 Thank you for your reply!
      I want to visualize distinct count of IDNR by other columns named 'Age group' and 'sex', and these columns exist only in Table 1, so the measure gives me the same value for all age group and sex, and I think its because these columns 'Age group' and 'sex' are not included in the selected columns. Is there another way to solve this?
      Thanks!

      • az38's avatar
        az38
        Community Champion
        6 years ago

        Anonymous 

        not sure I understand you correct, but if so you could execute the next workaround

        1. create a table

        IntersectTable= 
distinct(
INTERSECT(
SELECTCOLUMNS(FILTER(ALL('Table 1');YEAR('Table 1'[Date]) =2018);"IDNR";[IDNR]);
SELECTCOLUMNS(FILTER(ALL('Table 2');YEAR('Table 2'[Date]) =2018);"IDNR";[IDNR])
)
)

        this table will contain all distnct IDNR which exists in 2018 year

        2. create relationships between your table 1 table with 'Age group' and 'sex' columns by field IDNR.

        3. Visualize it as you wish. for example create table visual with columns:

        'IntersectTable'[IDNR]

        'Table1'[Age group]

        'Table1'[Sex]

         

        do not hesitate to give a kudo to useful posts and mark solutions as solution