We're giving away 30 tickets for FREE! Share your story, your vision, or your hustle and tell us why YOU deserve a ticket.
Apply nowWin a FREE 3 Day Ticket to FabCon Vienna. Apply now
I have two tables 'Table 1' and 'Table 2' both tables have column names ID.NR, Date, etc. these two tables are joined by IDNR, neither column contains unique values for column IDNR so the relation type is many to many and the cross filter direction is both.
I want to count distinct values of IDNR for Table 1, for the year 2018 if IDNR also exists in table 2. I tried to create a calculated column using the following formula but it didn't give me the right results.
Kolumn = CALCULATE(DISTINCTCOUNT(Table 1[IDNR]),FILTER(ALL(table 2)
,Table 2 [IDNR] = Table 1[IDNR] && Table 2[Year] = Table 1[Year]))
Hi @Anonymous
try something like that
= countrows(
distinct(
INTERSECT(
SELECTCOLUMNS(FILTER(ALL('Table 1');YEAR('Table 1'[Date]) =2018);"IDNR";[IDNR]);
SELECTCOLUMNS(FILTER(ALL('Table 2');YEAR('Table 2'[Date]) =2018);"IDNR";[IDNR])
)
)
)
do not hesitate to give a kudo to useful posts and mark solutions as solution
@az38 Thank you for your reply!
I want to visualize distinct count of IDNR by other columns named 'Age group' and 'sex', and these columns exist only in Table 1, so the measure gives me the same value for all age group and sex, and I think its because these columns 'Age group' and 'sex' are not included in the selected columns. Is there another way to solve this?
Thanks!
@Anonymous
not sure I understand you correct, but if so you could execute the next workaround
1. create a table
IntersectTable=
distinct(
INTERSECT(
SELECTCOLUMNS(FILTER(ALL('Table 1');YEAR('Table 1'[Date]) =2018);"IDNR";[IDNR]);
SELECTCOLUMNS(FILTER(ALL('Table 2');YEAR('Table 2'[Date]) =2018);"IDNR";[IDNR])
)
)
this table will contain all distnct IDNR which exists in 2018 year
2. create relationships between your table 1 table with 'Age group' and 'sex' columns by field IDNR.
3. Visualize it as you wish. for example create table visual with columns:
'IntersectTable'[IDNR]
'Table1'[Age group]
'Table1'[Sex]
do not hesitate to give a kudo to useful posts and mark solutions as solution
User | Count |
---|---|
60 | |
60 | |
47 | |
38 | |
34 |
User | Count |
---|---|
92 | |
81 | |
66 | |
48 | |
48 |