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Mammm25
Regular Visitor

Display content of a table if a condition is met

I have to display content of a table if a condition is meet. For example:

Mammm25_0-1689773747800.png

 

1 ACCEPTED SOLUTION
Anonymous
Not applicable

Hi @Mammm25 

You can refer to the following measure

The sample data 

Table 1

vxinruzhumsft_0-1689917906805.png

Table 2

vxinruzhumsft_1-1689917961919.png

Then create a measure, and put it tp the visual slicer

Measure = var a=SUMMARIZE(FILTER(ALLSELECTED('Table'),YEAR([Start])<=SELECTEDVALUE('Table (2)'[Column1])&&YEAR([End])>=SELECTEDVALUE('Table (2)'[Column1])),[Name])
return IF(ISFILTERED('Table (2)'[Column1]),IF(SELECTEDVALUE('Table'[Name]) in a=FALSE(),1,0),1)

vxinruzhumsft_2-1689918115207.png

Output

vxinruzhumsft_5-1689918192051.png

 

vxinruzhumsft_6-1689918204326.png

 

vxinruzhumsft_7-1689918211880.png

 

Best Regards!

Yolo Zhu

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

 

 

 

View solution in original post

2 REPLIES 2
Anonymous
Not applicable

Hi @Mammm25 

You can refer to the following measure

The sample data 

Table 1

vxinruzhumsft_0-1689917906805.png

Table 2

vxinruzhumsft_1-1689917961919.png

Then create a measure, and put it tp the visual slicer

Measure = var a=SUMMARIZE(FILTER(ALLSELECTED('Table'),YEAR([Start])<=SELECTEDVALUE('Table (2)'[Column1])&&YEAR([End])>=SELECTEDVALUE('Table (2)'[Column1])),[Name])
return IF(ISFILTERED('Table (2)'[Column1]),IF(SELECTEDVALUE('Table'[Name]) in a=FALSE(),1,0),1)

vxinruzhumsft_2-1689918115207.png

Output

vxinruzhumsft_5-1689918192051.png

 

vxinruzhumsft_6-1689918204326.png

 

vxinruzhumsft_7-1689918211880.png

 

Best Regards!

Yolo Zhu

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

 

 

 

lbendlin
Super User
Super User

Create a reference table with the desired name/year combinations and join it (many to many, gasp!  but single direction) via the name column.

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