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Anonymous
Not applicable

Datediff function is giving always negative values

Hi,

I am using the below expression:

Recv Split = DATEDIFF('Data'[LW_RECEIVE_END_DATE_TIME], 'Data'[LW_RECEIVE_START_DATE_TIME], SECOND)

and my source data is like below:

date Data.PNG

But I am always getting negative values. Please help me.

 

 

 

1 ACCEPTED SOLUTION
v-yuta-msft
Community Support
Community Support

@Anonymous ,

 

Start_Date should be in the first parameter position while End_Date be in the second parameter as below.

Capture.PNG 

 

Community Support Team _ Jimmy Tao

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

2 REPLIES 2
v-yuta-msft
Community Support
Community Support

@Anonymous ,

 

Start_Date should be in the first parameter position while End_Date be in the second parameter as below.

Capture.PNG 

 

Community Support Team _ Jimmy Tao

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Anonymous
Not applicable

Have you tried flipping the start and end times?

 

Ex. Recv Split = DATEDIFF('Data'[LW_RECEIVE_START_DATE_TIME],'Data'[LW_RECEIVE_END_DATE_TIME],  SECOND)

 

This is a really lazy work around but couldn't you multiply the function by -1? If it is always giving you negatives that should work. 

 

Ex. Recv Split = DATEDIFF('Data'[LW_RECEIVE_START_DATE_TIME],'Data'[LW_RECEIVE_END_DATE_TIME],  SECOND)*-1

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