Microsoft Fabric Community Conference 2025, March 31 - April 2, Las Vegas, Nevada. Use code FABINSIDER for a $400 discount.
Register nowGet inspired! Check out the entries from the Power BI DataViz World Championships preliminary rounds and give kudos to your favorites. View the vizzies.
Dear Power BI Community
Following Task to solve:
Let's assume this table:
We are looking for the date/time difference of an ID from the first to the last Occurence
Any ideas how to solve this problem?
Thank you very much for your contribution.
Cheers
qwertzuiop
Solved! Go to Solution.
Hi @qwertzuiop ,
Please try:
TimeDiff_from_FirstTime_to_LastTime =
var _a = MAXX(FILTER(ALL('Table'),[ID]=SELECTEDVALUE('Table'[ID])&&[CheckOccurence]="FirstTime"),[Date/time])
var _b = MAXX(FILTER(ALL('Table'),[ID]=SELECTEDVALUE('Table'[ID])&&[CheckOccurence]="LastTime"),[Date/time])
return DATEDIFF(_a,_b,MINUTE)/(60*24)
Final output:
Best Regards,
Jianbo Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @Mahesh0016
Hopefully with this visualisation I can better represent my desired output.
It is not necessarily important that the output is in the corresponding line. What is important is that somewhere there is information that, for example, ID MDY5MP takes approx. 3,999 days from first to lasttime (maybe best approach in a measure, no?)
Let me know if you need further information.
Thank you
Cheers qwertzuiop
Hi @qwertzuiop ,
Please try:
TimeDiff_from_FirstTime_to_LastTime =
var _a = MAXX(FILTER(ALL('Table'),[ID]=SELECTEDVALUE('Table'[ID])&&[CheckOccurence]="FirstTime"),[Date/time])
var _b = MAXX(FILTER(ALL('Table'),[ID]=SELECTEDVALUE('Table'[ID])&&[CheckOccurence]="LastTime"),[Date/time])
return DATEDIFF(_a,_b,MINUTE)/(60*24)
Final output:
Best Regards,
Jianbo Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
User | Count |
---|---|
86 | |
82 | |
42 | |
40 | |
35 |