cancel
Showing results for 
Search instead for 
Did you mean: 
Reply
Anonymous
Not applicable

Data model with 2 many to many fact tables

Hello,

 

I'm trying to build a report for employee time stamping, that has worker name, date, and personnelnumber as separate slicers. The report table has Date and several time stamps from the StampJournalTable as rows. I'm trying to include the lunch in/out times from StampJournalTrans in the report table. To achieve this, I'm building 2 calculated columns(Lunch in 2/Lunch out 2) that have data which corresponds the date and personnelnumber in StampJournalTable and have duplicate values. Also in StampJournalTrans both Date and Worker ID have duplicate values since there can be several worker stamps for each date.

 

I've tried to use the following DAX formulas for Lunch out 2 calculated column:

 

Lunch out 2 = LOOKUPVALUE(StampJournalTrans[LUNCH OUT], StampJournalTrans[WORKER ID], RELATED(Worker[WORKER ID]), StampJournalTrans[DATE], StampJournalTable[DATE])

 

Produces the error: "A table of multiple values was supplied where a single value was expected."

 

Lunch out 2 = CALCULATE(
FIRSTNONBLANK(StampJournalTrans[LUNCH OUT],1),
FILTER(StampJournalTrans, StampJournalTrans[DATE]=StampJournalTable[DATE]
&& StampJournalTrans[WORKER ID]=RELATED(Worker[WORKER ID])))

 

Produces wrong values. For example for a date when the worker has not made any other time stamps.

 

I have added a picture of my current data model, which has the keys between tables circled in red. I feel like I'm close to solving this but still can't quite figure it out. Any idea how I should fix my DAX formulas? I hope my explanation of the problem made sense. Thanks for any help.

 

Time&Attendance-Lunch.png

1 ACCEPTED SOLUTION
v-cherch-msft
Microsoft
Microsoft

Hi @Anonymous 

You may try to create a column like below:

Column =
CALCULATE (
    MAX ( StampJournalTrans[LUNCH OUT] ),
    FILTER (
        StampJournalTrans,
        StampJournalTrans[DATE] = StampJournalTable[DATE]
            && StampJournalTable[personnelnumber] = RELATED ( Worker[Personnelnumber] )
    )
)

Regards,

Community Support Team _ Cherie Chen
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

2 REPLIES 2
v-cherch-msft
Microsoft
Microsoft

Hi @Anonymous 

You may try to create a column like below:

Column =
CALCULATE (
    MAX ( StampJournalTrans[LUNCH OUT] ),
    FILTER (
        StampJournalTrans,
        StampJournalTrans[DATE] = StampJournalTable[DATE]
            && StampJournalTable[personnelnumber] = RELATED ( Worker[Personnelnumber] )
    )
)

Regards,

Community Support Team _ Cherie Chen
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Anonymous
Not applicable

That finally seems to have fixed it. Thank you so much @v-cherch-msft 

Helpful resources

Announcements
PBI Sept Update Carousel

Power BI September 2023 Update

Take a look at the September 2023 Power BI update to learn more.

Learn Live

Learn Live: Event Series

Join Microsoft Reactor and learn from developers.

Top Solution Authors