DAX Time Patterns

[mshakir]

I have to calculate Day no of month and Day no of quarter using dax help me please.

[amitchandak · Accepted solution]

@mshakir , You have startofmonth and startofquarter

take date diff from this you will get month day and quarter day

STQ = startofquarter(Date[Date])

Day of Qtr = datediff(STQ ,Date[Date],DAY)

[amitchandak · Accepted solution]

@mshakir , You have startofmonth and startofquarter

take date diff from this you will get month day and quarter day

STQ = startofquarter(Date[Date])

Day of Qtr = datediff(STQ ,Date[Date],DAY)

[az38]

Hi @mshakir 

Quarter No = QUARTER(Table[Date])

Day No = DAY(Table[Date])

https://docs.microsoft.com/en-us/dax/quarter-function-dax

https://docs.microsoft.com/en-us/dax/day-function-dax

[mshakir]

This is the date table and my perspective is to calculate columns (DayNoOfQuarter and DayNoOfMonth) same like DayNoOfYear as given in screenshot. i need Day Number for both Quarter and Month neither the Quarter Number nor the Month Number

[v-shex-msft · Accepted solution]

HI @mshakir,

You can direct create a new calculated column to use the 'day' function to extract the current day no of month. For 'day of quarter', you can refer to following calculated column formula:

DayofMonth=DAY('Calendar'[Date])

DayofQuarter =
VAR cQuarter =
    INT ( MONTH ( 'Calendar'[Date] ) / 3 )
        + IF (
            MONTH ( 'Calendar'[Date] ) < 3
                && MOD ( MONTH ( 'Calendar'[Date] ), 3 ) > 0,
            1,
            0
        )
RETURN
    COUNTROWS (
        CALENDAR (
            DATE ( YEAR ( 'Calendar'[Date] ), IF ( cQuarter > 1, ( cQuarter - 1 ) * 3, cQuarter ), 1 ),
            'Calendar'[Date]
        )
    )

Regards,

Xiaoxin Sheng