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Helper I

## DATEADD combined with filter function

Need help in building a report. it is necessary to show the number of orders for a similar period.

Using CALCULATE formula (COUNTROWS (Sheet1); DATEADD (Sheet1 [date]; - 7; DAY)) report obtained over a period of 7 days.

But what if the user selects a date with the help of the filter?

I used a new measure that would count the number of days in the period: CountDay = DATEDIFF (MIN (Sheet1 [date]); MAX (Sheet1 [date]); DAY).

Result inserted in the formula for the same period of recovery: SamePerVar2 = CALCULATE (COUNTROWS (Sheet1); DATEADD (Sheet1 [date]; - 'Sheet1' [CountDay] -1; DAY)).

As a result, I realized that in this measure there are always zero days.
Help improve the formula.

Thank you.

1 ACCEPTED SOLUTION
Employee

Hi @Anthony007,

Based on my test, you could refer to below steps:

1.Create a calender table and create relationship with your row table:

2.Create two measures:

`CountDay2 = VALUE(DATEDIFF (MIN ('Table'[Date]), MAX ('Table'[Date]), DAY))`
`Measure = CALCULATE(COUNT(Sheet1[id]),DATEADD('Table'[Date],[CountDay2],DAY))`

3.Use the calender data column as the slicer,

Result:

Regards,

Daniel He

Community Support Team _ Daniel He
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
2 REPLIES 2
Employee

Hi @Anthony007,

Based on my test, you could refer to below steps:

1.Create a calender table and create relationship with your row table:

2.Create two measures:

`CountDay2 = VALUE(DATEDIFF (MIN ('Table'[Date]), MAX ('Table'[Date]), DAY))`
`Measure = CALCULATE(COUNT(Sheet1[id]),DATEADD('Table'[Date],[CountDay2],DAY))`

3.Use the calender data column as the slicer,

Result:

Regards,

Daniel He

Community Support Team _ Daniel He
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Helper I

Many thanks for the response and help.

Creating a calendar table and relationships really helps in counting the number of days in a period. But at the same time, the date hierarchy is lost and the graph displays information in the wrong way:

And the result is the following:As if to compare this period with a similar one.

Perhaps there is another way to count the number of days in a period without creating a date table? Or try creating a date hierarchy manually?

I'm now trying to write a formula that simply considers the number of unique values ​​in the date column using DISTINCTCOUNT

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