Forum Discussion
Cumulative calcualtion on the same column
Hello All,
I have a table with various item and their value for dates. I have calculated the change of their value as return. Now I need to create a column that refers to its previous value of the same column. My data is as follows:
| Date | Type | Value | Return | Column |
| 1/1/2020 | A | 1 | 100 | |
| 1/2/2020 | A | 2 | 1 | 200 |
| 1/3/2020 | A | 3 | 0.5 | 101 |
| 1/4/2020 | A | 4 | 0.333333 | 134.6667 |
| 1/5/2020 | A | 5 | 0.25 | 102 |
| 1/1/2020 | B | 7 | 100 | |
| 1/2/2020 | B | 8 | 0.142857 | 103 |
| 1/3/2020 | B | 9 | 0.125 | 115.875 |
| 1/4/2020 | B | 10 | 0.111111 | 104 |
| 1/5/2020 | B | 11 | 0.1 | 114.4 |
I need to calculate the new column whose formula is:
if(return = 0), then 100
else previous value * (1+ return)
It is quite staright forward in excel. We can directly do, E4 = E3*(1+D4)
When i create a similar formula in DAX, i am getting a circular loop error. Any helps is appreciated.
Hi sonm10 ,
Please check if this is what you want:
Column 2 = VAR CurrentDate = [Date] VAR t = ADDCOLUMNS ( 'Table', "Return_1", [Return] + 1 ) RETURN PRODUCTX ( FILTER ( t, [Type] = EARLIER ( [Type] ) && [Date] <= CurrentDate ), [Return_1] ) * 100But I have some confusion. Is the data marked above written wrong?
Best Regards,
Icey
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
3 Replies
- amitchandak
Super User
sonm10 , try a new column
if(coalesce([Return],0) =0,100 , [value] * (1+ [return]))
if(([Return]+0) =0,100 , [value] * (1+ [return]))
- Icey
Community Support
Hi sonm10 ,
Please check if this is what you want:
Column 2 = VAR CurrentDate = [Date] VAR t = ADDCOLUMNS ( 'Table', "Return_1", [Return] + 1 ) RETURN PRODUCTX ( FILTER ( t, [Type] = EARLIER ( [Type] ) && [Date] <= CurrentDate ), [Return_1] ) * 100But I have some confusion. Is the data marked above written wrong?
Best Regards,
Icey
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.