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Anonymous
Not applicable

Creating new column using values from column A, conditional on columns B and C

Hi, I'm struggling a lot with this problem, any help would be appreciated

 

I have a table like this:

ABC
2417
1427
6437
2447
1357
4767
6277
34814
63914
351014
741114
351214
751314
351414


I want to create a new column such that:

If B != C for the row, then we want the value from A WHERE the C for the row in question = B from any of the rows.

Else if B == C, we wnat the value from A.

 

The resulting table looks like:

ABCNew column
241762
142762
643762
244762
135762
476762
627762
3481435
6391435
35101435
74111435
35121435
75131435
35141435

 

I have tried:

Weekend inventory = if(
[B]<>[C],SELECTCOLUMNS(filter(Table,[B]=[C]),"temp",[A]),
[A])
 
But this gives me an error which I assume is because there are multiple matching B and C values...
 
Any help would be really appreciated!!!!!!
1 ACCEPTED SOLUTION
Anonymous
Not applicable

Hi,

 

Try this formula

New Column = 
VAR a_val = 'Table'[A]
VAR b_val = 'Table'[B]
VAR c_val = 'Table'[C]
RETURN
IF (
    b_val <> c_val,
    LOOKUPVALUE( 'Table'[A], 'Table'[B], c_val),
    a_val)

View solution in original post

3 REPLIES 3
Anonymous
Not applicable

Hi,

 

Try this formula

New Column = 
VAR a_val = 'Table'[A]
VAR b_val = 'Table'[B]
VAR c_val = 'Table'[C]
RETURN
IF (
    b_val <> c_val,
    LOOKUPVALUE( 'Table'[A], 'Table'[B], c_val),
    a_val)
Anonymous
Not applicable

Thanks so much for your reply!!!

 

But I am getting this error for some reason:

"A table of multiple values was supplied where a single value was expected."

Anonymous
Not applicable

Look I think your formula is pretty sound - I'll go check my data to see if there are multiple matches between columns B and columns C.....

 

Thanks for your help!!!

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