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I want to create an intermediate table based on the relationship between two existing tables.
I have two existing tables; Tickets and Events.
Table: Tickets
ticket_id | guest_id | event_id |
1 | 1 | 1 |
2 | 2 | 2 |
Table: Events
event_id | host_id |
1 | 10 |
2 | 10 |
I want to create a table called TicketsToUser that ends up being like this:
ticket_id | guest_id | user_id | event_id |
1 | guest | 1 | 1 |
1 | host | 10 | 1 |
2 | guest | 2 | 2 |
2 | host | 10 | 2 |
Thanks in advance.
Solved! Go to Solution.
@twowaysyellow add following expression to create the table
Table =
VAR __Table =
SELECTCOLUMNS ( Tickets, "Ticket_Id", Tickets[ticket_id], "User_Id", Tickets[guest_id], "Event_Id", Tickets[event_id], "Host_Id", RELATED ( Events[host_id] ) )
RETURN
UNION (
ADDCOLUMNS (
SELECTCOLUMNS (
__Table,
[Ticket_Id], [User_Id], [Event_ID]
), "Guest_Id", "Guest"
),
ADDCOLUMNS (
SELECTCOLUMNS (
__Table,
[Ticket_Id], [Host_Id], [Event_ID]
), "Guest_Id", "Host"
)
)
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@twowaysyellow add following expression to create the table
Table =
VAR __Table =
SELECTCOLUMNS ( Tickets, "Ticket_Id", Tickets[ticket_id], "User_Id", Tickets[guest_id], "Event_Id", Tickets[event_id], "Host_Id", RELATED ( Events[host_id] ) )
RETURN
UNION (
ADDCOLUMNS (
SELECTCOLUMNS (
__Table,
[Ticket_Id], [User_Id], [Event_ID]
), "Guest_Id", "Guest"
),
ADDCOLUMNS (
SELECTCOLUMNS (
__Table,
[Ticket_Id], [Host_Id], [Event_ID]
), "Guest_Id", "Host"
)
)
Subscribe to the @PowerBIHowTo YT channel for an upcoming video on List and Record functions in Power Query!!
Learn Power BI and Fabric - subscribe to our YT channel - Click here: @PowerBIHowTo
If my solution proved useful, I'd be delighted to receive Kudos. When you put effort into asking a question, it's equally thoughtful to acknowledge and give Kudos to the individual who helped you solve the problem. It's a small gesture that shows appreciation and encouragement! ❤
Did I answer your question? Mark my post as a solution. Proud to be a Super User! Appreciate your Kudos 🙂
Feel free to email me with any of your BI needs.