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Hi ,
Date hire date
05-Aug-2020 05-aug-19
I need how many months diffrence Date and hire date,please help on this issues.
Regards,
Solved! Go to Solution.
@Anonymous , as new column
datediff([hire date],today(),Month)
or
datediff([hire date],[date],Month)
as a new measure // you need to take care of row context
datediff(min([hire date]),today(),Month)
or
datediff(min([hire date]),Max([date]),Month)
@Anonymous , as new column
datediff([hire date],today(),Month)
or
datediff([hire date],[date],Month)
as a new measure // you need to take care of row context
datediff(min([hire date]),today(),Month)
or
datediff(min([hire date]),Max([date]),Month)
@Anonymous,
Create a new column and use the DATEDIFF function.
Here's a link to how DATEDIFF works: https://docs.microsoft.com/en-us/dax/datediff-function-dax
For months difference between Hire_Date and Date, you will have to use below formula:
Month_Diff Col = DATEDIFF([hire date], [Date], MONTH)
For days difference between Hire_Date and Date, you will have to use below formula:
Day_Diff Col = DATEDIFF([hire date], [Date], DAY)
Give a thumbs up if this post helped you in any way and mark this post as solution if it solved your query !!!
Hi @Anonymous
try new column
Column = DATEDIFF([hire date], [Date], MONTH)
@Anonymous - Maybe:
Column =
VAR __HireYear = YEAR([hire date])
VAR __HireMonth = MONTH([hire date])
VAR __DateYear = YEAR([Date])
VAR __DateMonth = MONTH([Date])
RETURN
(__DateYear - __HireYear)*12 + (__HireMonth - __DateMonth)
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