Forum Discussion
Count Of Days In Month.
Hi ,
Date hire date
05-Aug-2020 05-aug-19
I need how many months diffrence Date and hire date,please help on this issues.
Regards,
Anonymous , as new column
datediff([hire date],today(),Month)
or
datediff([hire date],[date],Month)
as a new measure // you need to take care of row context
datediff(min([hire date]),today(),Month)
or
datediff(min([hire date]),Max([date]),Month)
4 Replies
- Greg_DecklerCommunity Champion
Anonymous - Maybe:
Column = VAR __HireYear = YEAR([hire date]) VAR __HireMonth = MONTH([hire date]) VAR __DateYear = YEAR([Date]) VAR __DateMonth = MONTH([Date]) RETURN (__DateYear - __HireYear)*12 + (__HireMonth - __DateMonth) - az38Community Champion
Hi Anonymous
try new column
Column = DATEDIFF([hire date], [Date], MONTH) - Anand24Super User
Anonymous,
Create a new column and use the DATEDIFF function.
Here's a link to how DATEDIFF works: https://docs.microsoft.com/en-us/dax/datediff-function-dax
For months difference between Hire_Date and Date, you will have to use below formula:
Month_Diff Col = DATEDIFF([hire date], [Date], MONTH)For days difference between Hire_Date and Date, you will have to use below formula:
Day_Diff Col = DATEDIFF([hire date], [Date], DAY)Give a thumbs up if this post helped you in any way and mark this post as solution if it solved your query !!!
- amitchandakSuper User
Anonymous , as new column
datediff([hire date],today(),Month)
or
datediff([hire date],[date],Month)
as a new measure // you need to take care of row context
datediff(min([hire date]),today(),Month)
or
datediff(min([hire date]),Max([date]),Month)