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Hello)
I have a problem could you please help me to count consecutive Months from the last available month in the data set for Users (column ID)
For example, for User 1 I want to have count 3 (3 months when a user with id 1 has values)
User 2 - the same 3
User 3 - 0 (because there is no values)
User 4 - 3 and so on
Maybe there are any chances to solve it?
Thank you so much for support.
Solved! Go to Solution.
Hi @yakovlol ,
Firstly, please make sure your table looks like as below.
Or you can try UNPIVOT function to translate it in Power Query Editor.
Measure:
Measure =
VAR _STEP1 =
ADDCOLUMNS (
'Table',
"Flag",
IF (
EOMONTH ( 'Table'[Date], 0 )
+ 1
IN CALCULATETABLE ( VALUES ( 'Table'[Date] ), ALLEXCEPT ( 'Table', 'Table'[ID] ) ),
1,
0
),
"MaxDate",
MAXX (
FILTER ( 'Table', 'Table'[ID] = EARLIER ( 'Table'[ID] ) ),
'Table'[Date]
)
)
VAR _STEP2 =
ADDCOLUMNS (
_STEP1,
"PrevioiusDate",
MAXX (
FILTER ( _STEP1, [ID] = EARLIER ( [ID] ) && [Date] < [MaxDate] && [Flag] = 0 ),
[Date]
)
)
RETURN
COUNTAX (
FILTER (
_STEP2,
[Date] > [PrevioiusDate]
&& [Date] <= [MaxDate]
&& [Value] <> 0
),
[ID]
)
Result is as below.
Best Regards,
Rico Zhou
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @yakovlol ,
Firstly, please make sure your table looks like as below.
Or you can try UNPIVOT function to translate it in Power Query Editor.
Measure:
Measure =
VAR _STEP1 =
ADDCOLUMNS (
'Table',
"Flag",
IF (
EOMONTH ( 'Table'[Date], 0 )
+ 1
IN CALCULATETABLE ( VALUES ( 'Table'[Date] ), ALLEXCEPT ( 'Table', 'Table'[ID] ) ),
1,
0
),
"MaxDate",
MAXX (
FILTER ( 'Table', 'Table'[ID] = EARLIER ( 'Table'[ID] ) ),
'Table'[Date]
)
)
VAR _STEP2 =
ADDCOLUMNS (
_STEP1,
"PrevioiusDate",
MAXX (
FILTER ( _STEP1, [ID] = EARLIER ( [ID] ) && [Date] < [MaxDate] && [Flag] = 0 ),
[Date]
)
)
RETURN
COUNTAX (
FILTER (
_STEP2,
[Date] > [PrevioiusDate]
&& [Date] <= [MaxDate]
&& [Value] <> 0
),
[ID]
)
Result is as below.
Best Regards,
Rico Zhou
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
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