Don't miss your chance to take the Fabric Data Engineer (DP-700) exam on us!
Learn moreWe've captured the moments from FabCon & SQLCon that everyone is talking about, and we are bringing them to the community, live and on-demand. Starts on April 14th. Register now
I have the following table. I need a calculated column that returns the count of consecutive LotNumber that has an increasing Amount. I have browsed similar solution but I cant get one to work on my table without crashing the pbix file
| Item | LotNumber | Amount | IncreasingConsecutiveCount |
| Table | 1 | 10 | 1 |
| Table | 3 | 20 | 2 |
| Table | 5 | 30 | 3 |
| Table | 9 | 20 | 1 |
| Table | 11 | 10 | 1 |
| Table | 13.6 | 20 | 2 |
| Table | 16.2 | 90 | 3 |
| Table | 18.8 | 10 | 1 |
| Table | 21.4 | 11 | 2 |
| Table | 24 | 12 | 3 |
| Table | 25 | 13 | 4 |
| Table | 26 | 14 | 5 |
Solved! Go to Solution.
You can try the following modified calculated columns
Rank =
RANKX (
FILTER ( 'Table', [Item] = EARLIER ( 'Table'[Item] ) ),
[LotNumber],
,
ASC
)
Flag =
VAR a =
CALCULATE (
SUM ( 'Table'[Amount] ),
ALLEXCEPT ( 'Table', 'Table'[Item] ),
'Table'[Rank]
= EARLIER ( 'Table'[Rank] ) - 1
)
RETURN
IF ( [Amount] > a, 1, 0 )
ConsecutiveCount =
VAR a =
MAXX (
FILTER (
'Table',
[Flag] = 0
&& [Item] = EARLIER ( 'Table'[Item] )
&& [Rank] <= EARLIER ( 'Table'[Rank] )
),
[Rank]
)
RETURN
SWITCH ( TRUE (), a = BLANK (), [Rank], [Rank] = a, 1, [Rank] - a + 1 )
Output
Best Regards!
Yolo Zhu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Thank you for that. Would you know why when you add another column everything turns to 1?
Hi,
Thanks for the solution @ThxAlot provided, it is excellent, and i want to offer some more information for user to refer to.
hello @PowerBITestingG , based on your descriotion, you can create the following calcualted columns.
Rank = RANKX('Table',[LotNumber],,ASC)Flag =
VAR a =
LOOKUPVALUE ( 'Table'[Amount], [Rank], [Rank] - 1 )
RETURN
IF ( [Amount] > a, 1, 0 )
ConsecutiveCount =
VAR a =
MAXX (
FILTER ( 'Table', [Flag] = 0 && [Rank] <= EARLIER ( 'Table'[Rank] ) ),
[Rank]
)
RETURN
SWITCH ( TRUE (), a = BLANK (), [Rank], [Rank] = a, 1, [Rank] - a + 1 )
Output
Best Regards!
Yolo Zhu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
The issue now is that if you use the entire dummy data I shared (with Item Chair), the code stops working
You can try the following modified calculated columns
Rank =
RANKX (
FILTER ( 'Table', [Item] = EARLIER ( 'Table'[Item] ) ),
[LotNumber],
,
ASC
)
Flag =
VAR a =
CALCULATE (
SUM ( 'Table'[Amount] ),
ALLEXCEPT ( 'Table', 'Table'[Item] ),
'Table'[Rank]
= EARLIER ( 'Table'[Rank] ) - 1
)
RETURN
IF ( [Amount] > a, 1, 0 )
ConsecutiveCount =
VAR a =
MAXX (
FILTER (
'Table',
[Flag] = 0
&& [Item] = EARLIER ( 'Table'[Item] )
&& [Rank] <= EARLIER ( 'Table'[Rank] )
),
[Rank]
)
RETURN
SWITCH ( TRUE (), a = BLANK (), [Rank], [Rank] = a, 1, [Rank] - a + 1 )
Output
Best Regards!
Yolo Zhu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
If you have recently started exploring Fabric, we'd love to hear how it's going. Your feedback can help with product improvements.
A new Power BI DataViz World Championship is coming this June! Don't miss out on submitting your entry.
Share feedback directly with Fabric product managers, participate in targeted research studies and influence the Fabric roadmap.
| User | Count |
|---|---|
| 53 | |
| 37 | |
| 34 | |
| 19 | |
| 17 |
| User | Count |
|---|---|
| 72 | |
| 72 | |
| 38 | |
| 35 | |
| 26 |