Forum Discussion
Convert multiple rows same date into on rows and convert other rows into columns
Hello , please I need help to do this ..I need to convert this table
| Date | Value |
| 2021-08-09 | 10 |
| 2021-08-09 | 20 |
| 2021-08-09 | 30 |
| 2021-08-10 | 50 |
to be in this format
| 30 | 20 | 10 | 2021-08-09 |
| 50 | 2021-08-10 |
How I can do this ?
- Anonymous5 years ago
Hi ayaasfour
There is a simple method that can be implemented directly in the Matrix, but the result display will be a little different, you can refer to it .
Put the value column in Columns and Values at the same time in Visual Format .
Best Regards
Community Support Team _ Ailsa Tao
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi,
This M code works
let Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMrDUNbDQNTIwMlTSUTI0UIrVQRMzwiJmDBEzNEASMwWKxQIA", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Date = _t, Value = _t]), #"Changed Type" = Table.TransformColumnTypes(Source,{{"Date", type date}, {"Value", Int64.Type}}), Partition = Table.Group(#"Changed Type", {"Date"}, {{"Partition", each Table.AddIndexColumn(_, "Index",1,1), type table}}), #"Expanded Partition" = Table.ExpandTableColumn(Partition, "Partition", {"Value", "Index"}, {"Value", "Index"}), #"Pivoted Column" = Table.Pivot(Table.TransformColumnTypes(#"Expanded Partition", {{"Index", type text}}, "en-IN"), List.Distinct(Table.TransformColumnTypes(#"Expanded Partition", {{"Index", type text}}, "en-IN")[Index]), "Index", "Value") in #"Pivoted Column"Hope this helps.
4 Replies
- amitchandakSuper User
ayaasfour , not excat same display
create a rank column in table
rank = rankx(filter(Table, [Date] = earlier([Date]) ),[Value])
Create a matrix with Rank as the column date as row, value on values
- ayaasfourFrequent Visitor
Can not be solved using matrix?
- AnonymousNot applicable
Hi ayaasfour
There is a simple method that can be implemented directly in the Matrix, but the result display will be a little different, you can refer to it .
Put the value column in Columns and Values at the same time in Visual Format .
Best Regards
Community Support Team _ Ailsa Tao
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
- Ashish_MathurSuper User
Hi,
This M code works
let Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMrDUNbDQNTIwMlTSUTI0UIrVQRMzwiJmDBEzNEASMwWKxQIA", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Date = _t, Value = _t]), #"Changed Type" = Table.TransformColumnTypes(Source,{{"Date", type date}, {"Value", Int64.Type}}), Partition = Table.Group(#"Changed Type", {"Date"}, {{"Partition", each Table.AddIndexColumn(_, "Index",1,1), type table}}), #"Expanded Partition" = Table.ExpandTableColumn(Partition, "Partition", {"Value", "Index"}, {"Value", "Index"}), #"Pivoted Column" = Table.Pivot(Table.TransformColumnTypes(#"Expanded Partition", {{"Index", type text}}, "en-IN"), List.Distinct(Table.TransformColumnTypes(#"Expanded Partition", {{"Index", type text}}, "en-IN")[Index]), "Index", "Value") in #"Pivoted Column"Hope this helps.