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bruppert
Frequent Visitor

Complex Date Filter

Hello,

 

I want to create a visual level filter (a measure) that filters the rows to a certain date range based on a date selected from a different column.

 

Both of these columns are in the data set that my report shares a live connection with. In my report, I have created a table that includes the [StartDate] column but not [AsOfDate]. What I want is a filter to only include rows that have [StartDate] after MAX([AsOfDate]) - 3 AND  before MAX([AsOfDate]) + 30.

 

 

Thank you!

1 ACCEPTED SOLUTION
v-xuding-msft
Community Support
Community Support

Hi @bruppert ,

 

In this scenario, I create a measure to calculate the sum of values in selected date.  If I understand incorrectly, please post the sample data and your expected output.

 

I create two tables. And there is not a relationship between them.

0.jpg

Measure = CALCULATE(VALUES(Table2[values]),FILTER(ALLSELECTED(Table2[StartDate]), MIN(Table2[StartDate]) >= MAX(Table1[AsOfDate])-3 && MAX(Table2[StartDate]) <= MAX(Table1[AsOfDate]) + 30))

1.jpg

 

Best Regards,

Xue Ding

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

Best Regards,
Xue Ding
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

1 REPLY 1
v-xuding-msft
Community Support
Community Support

Hi @bruppert ,

 

In this scenario, I create a measure to calculate the sum of values in selected date.  If I understand incorrectly, please post the sample data and your expected output.

 

I create two tables. And there is not a relationship between them.

0.jpg

Measure = CALCULATE(VALUES(Table2[values]),FILTER(ALLSELECTED(Table2[StartDate]), MIN(Table2[StartDate]) >= MAX(Table1[AsOfDate])-3 && MAX(Table2[StartDate]) <= MAX(Table1[AsOfDate]) + 30))

1.jpg

 

Best Regards,

Xue Ding

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

Best Regards,
Xue Ding
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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