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Hi there,
How the Card values work showing Total as 200 , Completed as 11 and Pending as 186 , even when there other filter applied. ?
My sample model card value is different value when the filter selection is done, but my requirement is the card values should show this values
Total as 200 , Completed as 11 and Pending as 186 even there is filter selection.
Solved! Go to Solution.
you can try to change visual interactions.
https://docs.microsoft.com/en-us/power-bi/create-reports/service-reports-visual-interactions
Proud to be a Super User!
you can try to change visual interactions.
https://docs.microsoft.com/en-us/power-bi/create-reports/service-reports-visual-interactions
Proud to be a Super User!
@suvechha , If Completed and Pending are values of dimension say status then
Calculate(Count(Table[Col]), all(Table[Status]))
or
Calculate(Count(Table[Col]), allselected(Table[Status]))
if they are meausre on different columns
[Completed] +[Pending]
Can you share sample data and sample output in table format? Or a sample pbix after removing sensitive data.
Hi Amit,
They are measures-
Completed :--
Hi, @suvechha
Use the "all" function to limit current tables in the filter condition.
New Pending =
CALCULATE (
DISTINCTCOUNT ( ChangeDetails[CHANGEID] ),
FILTER(ALL('Change_StageDefinition'),Change_StageDefinition[DISPLAYNAME] <> "Close"
),FILTER(ALL('Change_StatusDefinition'),Change_StatusDefinition[STATUSDISPLAYNAME] <> "Completed" && Change_StatusDefinition[STATUSDISPLAYNAME] <> "Cancelled"
))
New Total = CALCULATE( [Total],ALL(Change_StatusDefinition),ALL(Change_StageDefinition))
New Completed =
CALCULATE (
DISTINCTCOUNT ( ChangeDetails[CHANGEID] ),
FILTER(ALL('Change_StageDefinition'),Change_StageDefinition[DISPLAYNAME]= "Close"
),FILTER(ALL('Change_StatusDefinition'),Change_StatusDefinition[STATUSDISPLAYNAME]="Completed"
))
For more details ,please check attached pbix file.
As mentioned by @ryan_mayu ,you can also directly disable the interaction between card visuals and each slicer.
Best Regards,
Community Support Team _ Eason
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
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