Forum Discussion
Calculating time duration
Hi!
I have a data for employees where they check in and check out everytime they enter the building. I want to calculate the time duration per day (I have a date slicer)
For instance here I want to subtract 5:55pm from 7:59am to get 9hrs 56min total hours.
I appreciate any help!
Hi, Alanoudfahad
Please check the below picture and the measure.
Result =VAR currentid =MAX ( Data[ID] )VAR currentdate =MAX ( Data[Date] )VAR minintime =CALCULATE (MIN ( Data[Time] ),FILTER (ALL ( Data ),Data[ID] = currentid&& Data[Date] = currentdate&& Data[In/Out] = "In"))VAR maxouttime =CALCULATE (MAX ( Data[Time] ),FILTER (ALL ( Data ),Data[ID] = currentid&& Data[Date] = currentdate&& Data[In/Out] = "Out"))RETURNmaxouttime - minintimeHi, My name is Jihwan Kim.
If this post helps, then please consider accept it as the solution to help other members find it faster, and give a big thumbs up.
Linkedin: linkedin.com/in/jihwankim1975/
Twitter: twitter.com/Jihwan_JHKIM
4 Replies
- Jihwan_KimSuper User
Hi, Alanoudfahad
Please check the below picture and the measure.
Result =VAR currentid =MAX ( Data[ID] )VAR currentdate =MAX ( Data[Date] )VAR minintime =CALCULATE (MIN ( Data[Time] ),FILTER (ALL ( Data ),Data[ID] = currentid&& Data[Date] = currentdate&& Data[In/Out] = "In"))VAR maxouttime =CALCULATE (MAX ( Data[Time] ),FILTER (ALL ( Data ),Data[ID] = currentid&& Data[Date] = currentdate&& Data[In/Out] = "Out"))RETURNmaxouttime - minintimeHi, My name is Jihwan Kim.
If this post helps, then please consider accept it as the solution to help other members find it faster, and give a big thumbs up.
Linkedin: linkedin.com/in/jihwankim1975/
Twitter: twitter.com/Jihwan_JHKIM
- AlanoudfahadFrequent Visitor
Works wonderfully, thanks!
- amitchandakSuper User
Alanoudfahad , Try a new column like
var _max = if([In/out] = "Out" , max(filter(Table, [Date] =earlier([Date]) && [Id] =earlier([ID]) && [In/out] ="In" && [Time] <earlier([Time])),[Time]), blank())
return
if([In/out] = "Out" && not(isblank(_max)) , datediff(_max, [Time], minute))/60Ideally in place of time you should use date time column
date time =[date]+[time]
- AlanoudfahadFrequent Visitor
Hi amitchandak It gives me this error "The expression refers to multiple columns. Multiple columns cannot be converted to a scalar value." even after crreating date/time column