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Erf19
Frequent Visitor

CalculateTable - Create rows with two columns and their distinct values

Hello,

 

I have a table like this:

PersonWeek NumberValue

A

1100
A250
A320
B150
B310
C115
C255

 

What I want is to take the unique values for Person and the unique values for Date and make a row for each unique pair, to create a new table like this:

PersonWeek Number
A1
A2
A3
B1
B2
B3
C1
C2
C3

 

That way, where for example person B doesn't have an entry for week 2, I can add a lookup column on the new table and say the value is 0.

 

Is there a formula to create this new table? I am thinking union, product, summarize.... not sure!

1 ACCEPTED SOLUTION
Greg_Deckler
Super User
Super User

@Erf19 - Try:

Table =
  GENERATE(
    DISTINCT('Table'[Person]),
    DISTINCT('Table'[Week])
  )

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2 REPLIES 2
Greg_Deckler
Super User
Super User

@Erf19 - Try:

Table =
  GENERATE(
    DISTINCT('Table'[Person]),
    DISTINCT('Table'[Week])
  )

Follow on LinkedIn
@ me in replies or I'll lose your thread!!!
Instead of a Kudo, please vote for this idea
Become an expert!: Enterprise DNA
External Tools: MSHGQM
YouTube Channel!: Microsoft Hates Greg
Latest book!:
The Definitive Guide to Power Query (M)

DAX is easy, CALCULATE makes DAX hard...
amitchandak
Super User
Super User

@Erf19 , Try a new Table like 

union(
addcolumns(except(crossjoin(distinct(Table[Person]),distinct(Table[Week])), selectcolumn(Table,"Person",[Person],"Week",[Week])),"Number Value",0),
Table)

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