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Hi BI Community Team,
We have a data of visited by sales rep and want to calculate the total working time spent that normally we have a time session/group: morning, lunch, afternoon, evening.
With these session, we consider the working time based on check-in (earliest) and check-in (latest).
Any suggestion/advise how to calculate and find out the total working time by day & month of each sales rep?
Thanks and Regards,
Solved! Go to Solution.
Hi @ADSL ,
There are several approaches to this:
1. To create a single measure of a virtual table summarizing the earliest and latest check-ins by code, group, and date, calculate the difference between the check-in and summing up the difference.
Time =
SUMX (
ADDCOLUMNS (
//virtual table
SUMMARIZE ( Data, Data[SR_CODE], Data[Time_Group], Data[CALL_DATE] ),
"Earliest Check-in",
CALCULATE (
MIN ( Data[Check-In] ),
ALLEXCEPT ( Data, Data[SR_CODE], Data[Time_Group], Data[CALL_DATE] )
),
"Latest Check-in",
CALCULATE (
MAX ( Data[Check-In] ),
ALLEXCEPT ( Data, Data[SR_CODE], Data[Time_Group], Data[CALL_DATE] )
)
),
//aggregate the difference
[Latest Check-in] - [Earliest Check-in]
)
//multiply the result by 24 to get the time in hours
2. Create several calculated columns for the earliest and latest check-ins and the difference. I personally prefer this as it is easy to visualize the calculations behind. Eeasier to troubleshoot as well. Result can be viewed in the data view.
Earliest Check-in =
CALCULATE (
MIN ( Data[Check-In] ),
FILTER (
FILTER (
FILTER ( Data, Data[SR_CODE] = EARLIER ( Data[SR_CODE] ) ),
Data[CALL_DATE] = EARLIER ( Data[CALL_DATE] )
),
Data[Time_Group] = EARLIER ( Data[Time_Group] )
)
)
Latest Check-in =
CALCULATE (
MAX ( Data[Check-In] ),
FILTER (
FILTER (
FILTER ( Data, Data[SR_CODE] = EARLIER ( Data[SR_CODE] ) ),
Data[CALL_DATE] = EARLIER ( Data[CALL_DATE] )
),
Data[Time_Group] = EARLIER ( Data[Time_Group] )
)
)
Difference = Data[Latest Check-in] - Data[Earliest Check-in]
And to get the sum create a measure of a virtual table summarizing the difference by group, code and date. Outright sum of the difference column will give a wrong result.
Time2 =
SUMX (
SUMMARIZE ( Data, Data[SR_CODE], Data[Time_Group], Data[CALL_DATE], Data[Difference] ),
Data[Difference]
)
//multiply by 24 to get the sum in hours
Please see attached sammple pbix.
Hi @ADSL ,
There are several approaches to this:
1. To create a single measure of a virtual table summarizing the earliest and latest check-ins by code, group, and date, calculate the difference between the check-in and summing up the difference.
Time =
SUMX (
ADDCOLUMNS (
//virtual table
SUMMARIZE ( Data, Data[SR_CODE], Data[Time_Group], Data[CALL_DATE] ),
"Earliest Check-in",
CALCULATE (
MIN ( Data[Check-In] ),
ALLEXCEPT ( Data, Data[SR_CODE], Data[Time_Group], Data[CALL_DATE] )
),
"Latest Check-in",
CALCULATE (
MAX ( Data[Check-In] ),
ALLEXCEPT ( Data, Data[SR_CODE], Data[Time_Group], Data[CALL_DATE] )
)
),
//aggregate the difference
[Latest Check-in] - [Earliest Check-in]
)
//multiply the result by 24 to get the time in hours
2. Create several calculated columns for the earliest and latest check-ins and the difference. I personally prefer this as it is easy to visualize the calculations behind. Eeasier to troubleshoot as well. Result can be viewed in the data view.
Earliest Check-in =
CALCULATE (
MIN ( Data[Check-In] ),
FILTER (
FILTER (
FILTER ( Data, Data[SR_CODE] = EARLIER ( Data[SR_CODE] ) ),
Data[CALL_DATE] = EARLIER ( Data[CALL_DATE] )
),
Data[Time_Group] = EARLIER ( Data[Time_Group] )
)
)
Latest Check-in =
CALCULATE (
MAX ( Data[Check-In] ),
FILTER (
FILTER (
FILTER ( Data, Data[SR_CODE] = EARLIER ( Data[SR_CODE] ) ),
Data[CALL_DATE] = EARLIER ( Data[CALL_DATE] )
),
Data[Time_Group] = EARLIER ( Data[Time_Group] )
)
)
Difference = Data[Latest Check-in] - Data[Earliest Check-in]
And to get the sum create a measure of a virtual table summarizing the difference by group, code and date. Outright sum of the difference column will give a wrong result.
Time2 =
SUMX (
SUMMARIZE ( Data, Data[SR_CODE], Data[Time_Group], Data[CALL_DATE], Data[Difference] ),
Data[Difference]
)
//multiply by 24 to get the sum in hours
Please see attached sammple pbix.