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Adhavan
Frequent Visitor

Calculate Average Order frequency

Hi All,

I have dataset like below, I want to show =Average order frequency.

 

Like, we are reciving the order for every X minutes. 

 

I have tried different calculation as suggested by in the forum. But, couldn't get the expected result.

 

653DA77F-22F8-4834-A6C4-F83DB13092DC.jpeg

2 ACCEPTED SOLUTIONS

Hi @Adhavan ,

 

Here I suggest you to try this code to create a calculated column.

Diff column =
VAR _LASTORDER =
    CALCULATE ( MIN ( 'Table'[order id] ), ALLEXCEPT ( 'Table', 'Table'[date] ) )
VAR _DIFF =
    [Datetime]
        - MAXX (
            FILTER ( 'Table', 'Table'[order id] = EARLIER ( 'Table'[order id] ) - 1 ),
            [Datetime]
        )
RETURN
    IF ( 'Table'[order id] = _LASTORDER, BLANK (), _DIFF )

Result is as below.

RicoZhou_0-1665040267276.png

 

Best Regards,
Rico Zhou

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

mangaus1111
Solution Sage
Solution Sage

Hi @Adhavan ,

it is a best practice to avoid using EARLIER to make the code easier to author and maintain, using variable (VAR), like in this example:
 
Diff column =
VAR FirstOrder_of_the_Day =
    CALCULATE (
             MIN ( 'Table'[Order ID] ),
             ALLEXCEPT ( 'Table', 'Table'[Date] )
             )

VAR Order_ID = 'Table'[Order ID]

VAR Diff =
    [DateTime]
        - MAXX (
                FILTER ('Table',
                        'Table'[Order ID] = Order_ID - 1
                       ),
                [DateTime]
        )
RETURN
    IF (
        'Table'[Order ID] = FirstOrder_of_the_Day,
        BLANK(),
        Diff
    )

 

 

View solution in original post

5 REPLIES 5
mangaus1111
Solution Sage
Solution Sage

Hi @Adhavan ,

it is a best practice to avoid using EARLIER to make the code easier to author and maintain, using variable (VAR), like in this example:
 
Diff column =
VAR FirstOrder_of_the_Day =
    CALCULATE (
             MIN ( 'Table'[Order ID] ),
             ALLEXCEPT ( 'Table', 'Table'[Date] )
             )

VAR Order_ID = 'Table'[Order ID]

VAR Diff =
    [DateTime]
        - MAXX (
                FILTER ('Table',
                        'Table'[Order ID] = Order_ID - 1
                       ),
                [DateTime]
        )
RETURN
    IF (
        'Table'[Order ID] = FirstOrder_of_the_Day,
        BLANK(),
        Diff
    )

 

 

amitchandak
Super User
Super User

@Adhavan , In case Order ID are incremental only 

 

a new column

 

Datetime= [Date]+ [Time]

 

Diff column =

[Datetime] - maxx(filter(Table, [Order_id] = earlier([Order_id]) -1) ,[Datetime] )

 

a Measure

 

Average(Table[Diff column])

 

 

 

@amitchandak ,

 

Its provided the result at each column. But, it calculate wrong average value due to following reason, which I couldn't elimate nor find the solution.

 

1. It calculates 18 hours for Jan' 1st alone.

2. It showing 12+ hours for every first order of the day (calculating from previous day)

 

I have attached the reference image. Could you help me to rid out of that.

 

C9E8D84B-2E9E-4037-8C61-495E15D8B83C.jpegE0CC8A69-8107-4B7B-9BC4-B580EA4A86EE.jpeg 

Hi @Adhavan ,

 

Here I suggest you to try this code to create a calculated column.

Diff column =
VAR _LASTORDER =
    CALCULATE ( MIN ( 'Table'[order id] ), ALLEXCEPT ( 'Table', 'Table'[date] ) )
VAR _DIFF =
    [Datetime]
        - MAXX (
            FILTER ( 'Table', 'Table'[order id] = EARLIER ( 'Table'[order id] ) - 1 ),
            [Datetime]
        )
RETURN
    IF ( 'Table'[order id] = _LASTORDER, BLANK (), _DIFF )

Result is as below.

RicoZhou_0-1665040267276.png

 

Best Regards,
Rico Zhou

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

@v-rzhou-msft 

 

Thanks a lot.

 

It shows the exact result I want.

 

Thank,

Mani

 

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