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Anonymous's avatar
Anonymous
Not applicable
4 years ago
Solved

CALCULATETABLE syntax?

Hello

 

Can CALCULATETABLE create a table from another table using:

1) columns matching (in) a specific list/array of column names

2) rows for each separately or all of the above filtered columns, matching specific criteria

 

So for example from the source table below:

Col1Col2Col3
A01/01/20001
B02/01/20002
C03/01/20003

 

To be able to CALCULATETABLE the below:

Col1Col3
A2
B4

 

By choosing all columns that are in the list {Col1,Col3} and all rows that match Col2=CALCULATE(MAX(Col2),ALLEXCEPT(Col1)) (i.e. the rows where Col2 is the maximum date for each value of Col1.

 

I think the CALCULATETABLE, ADDCOLUMNS, SELECTCOLUMNS accept literal Column Names and not expressions and also you need to specify each one by one and not in a list?

 

Thanks! 

  • Anonymous's avatar
    Anonymous
    4 years ago

    Hi Anonymous ,

     

    I think you may try this code to create a new table.

    Table 2 = 
    SELECTCOLUMNS (
        FILTER (
            'Table',
            VAR _MAX_COL2 =
                CALCULATE ( MAX ( 'Table'[Col2] ), ALLEXCEPT ( 'Table', 'Table'[Col1] ) )
            RETURN
                'Table'[Col2] = _MAX_COL2
        ),
        "Col1", 'Table'[Col1],
        "Col3", 'Table'[Col3]
    )

    My Sample:

    Result is as below.

     

    Best Regards,
    Rico Zhou

     

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

2 Replies

  • Anonymous's avatar
    Anonymous
    Not applicable

    Hi Anonymous ,

     

    I think you may try this code to create a new table.

    Table 2 = 
    SELECTCOLUMNS (
        FILTER (
            'Table',
            VAR _MAX_COL2 =
                CALCULATE ( MAX ( 'Table'[Col2] ), ALLEXCEPT ( 'Table', 'Table'[Col1] ) )
            RETURN
                'Table'[Col2] = _MAX_COL2
        ),
        "Col1", 'Table'[Col1],
        "Col3", 'Table'[Col3]
    )

    My Sample:

    Result is as below.

     

    Best Regards,
    Rico Zhou

     

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

  • littlemojopuppy's avatar
    littlemojopuppy
    Community Champion

    Hi Anonymous 

     

    Take a look at the GENERATE function.  It allows you to create joins where there may not be lineage.

    This isn't going to be syntactically accurate because I'm typing it in Notepad.  But it should get you close...

    GENERATE(
    	TableA,
    	FILTER(
    		TableB,
    		Col1 = EARLIER(TableA[Col1)
    	)
    )

    Hope this helps!