Average calculation

[pva]

Hi all! I want to calculate an average this way

I have this table:

Code	Period	Hours
5125	201902	2
5125	201903	4
5125	201903	6
5125	201904	3
5125	201905	4

So, if I calculate it with the average function the calculation would be like this:

(2+4+6+3+4)/5 = 3,8

But I don't want this way of calculating it. The way I want is, first, calculating the average per period and finally calculating the average of those averages. Example:

Avg 2019/02 = 2

Avg 2019/03 = 5 

Avg 2019/04 = 3

Avg 2019/04 = 4

So the final average would be 4,25 -> (2+5+3+4)/4

Any idea of how to solve it?

Thank you all!!

[Anonymous · Accepted solution]

Hi @pva 

How did you get 4.5 when you use (2+5+3+4)/4 ? The correct answer is 3.5 .

For 5125 , the final result is 3.5 -> ((4+6)/2+2+3+4)/4 .For 2147 , the final result is 4.667 -> ((2+4)/2+8+3)/3 . So the final average is 4.08 ->(3.5+4.667)/2

To realize the final average , you need to nest an AVERAGEX() outside the formula provided by SU .

Avg =AVERAGEX(VALUES('Table'[Code]),calculate(AVERAGEX(VALUES('Table'[Period]),CALCULATE(AVERAGE('Table'[Hours])))))

The final result is as shown :

I have attached my pbix file , you can refer to it .

Best Regard

Community Support Team _ Ailsa Tao

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

[parry2k]

@pva try this measure

Avg = 
AVERAGEX ( VALUES ( Table[Period] ), CALCULATE ( AVERGAGE ( Table[Hours] ) ) )

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[pva]

Thank for your help. In the table there are more codes. The table would be like this:

Code	Period	Hours
5125	201902	2
5125	201903	4
5125	201903	6
5125	201904	3
5125	201905	4
2147	201902	2
2147	201902	4
2147	201903	8
2147	201904	3

So the global average should be: 

5125 -> 4,25

2147 -> 3,66 (2+((4+8)/2)+3)/3

Total avg = (4,25+3,66)/2 = 3,955