Skip to main content
cancel
Showing results for 
Search instead for 
Did you mean: 

Join the OneLake & Platform Admin teams for an ask US anything on July 16th. Join now.

Reply
BoSe
Frequent Visitor

Unable to get list of files with ABFS path

Hello,

i added multiple lakehouses toone notebook.

Now i want to check what is the latest file in a specific folder in each of the lakehouses.

 

I'm able to access the data using the 'File API path' of the default Lakehouse:

 

list_of_files = glob.glob('/lakehouse/default/Files/.../input/*') 
last_modified_file = max(list_of_files, key=os.path.getmtime)
last_modified_file

 

 

 

However when i try to do the same with ABFS Path, i dont get a result in list_of_files. It just returns an empty list:

 

list_of_files = glob.glob('abfss://.../input/*')
list_of_files

 

 

If i try to read data with the ABFS Path i works without any issue- so i can not be an issue with path/permission:

 

df = pd.read_csv('abfss://...input/example.csv',sheet_name="Tabelle1")

 

 

 

Any idea how to make it work that not only the default lakehouse can be accessed but also another as datasource added lakehouses?

1 ACCEPTED SOLUTION
Anonymous
Not applicable

Hi @BoSe ,

Thanks for using Fabric Community.
It looks like glob is not able to process it when we are passing the abfs path. This looks like a limitation with glob.

You can also try mssparkutils.fs.ls - Introduction to Microsoft Spark utilities - Azure Synapse Analytics | Microsoft Learn

 

files = mssparkutils.fs.ls("abfss://5e****dd/Files")
file_paths = [f.path for f in files]
print(file_path)

 


Hope this is helpful. Please let me know incase of further queries.

View solution in original post

4 REPLIES 4
Anonymous
Not applicable

Hi @BoSe ,

Thanks for using Fabric Community.
It looks like glob is not able to process it when we are passing the abfs path. This looks like a limitation with glob.

You can also try mssparkutils.fs.ls - Introduction to Microsoft Spark utilities - Azure Synapse Analytics | Microsoft Learn

 

files = mssparkutils.fs.ls("abfss://5e****dd/Files")
file_paths = [f.path for f in files]
print(file_path)

 


Hope this is helpful. Please let me know incase of further queries.

I was able to get the latest file (with all the info), with this addition:

 

latest_file = max(files, key=lambda file: file.modifyTime)

Thanks for the input.

 

You get the path.. but it does not work with abfss path

Anonymous
Not applicable

Glad to know your query got resolved. Please continue using Fabric Communty for your further queries.

Helpful resources

Announcements
Join our Fabric User Panel

Join our Fabric User Panel

This is your chance to engage directly with the engineering team behind Fabric and Power BI. Share your experiences and shape the future.

June FBC25 Carousel

Fabric Monthly Update - June 2025

Check out the June 2025 Fabric update to learn about new features.

June 2025 community update carousel

Fabric Community Update - June 2025

Find out what's new and trending in the Fabric community.

Top Solution Authors