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Easley06
Helper II
Helper II

(latest date - transaction date) - non working days

Hi,

 

would like to ask for possible solution for this 

i have column for today and transaction date i want also to exclude weekend/holiday 

Easley06_0-1661174845294.png

 

based on this columns

image.png

 

Measure = Total count of records 
((ABS(current date - date_reported)) - nonworking days)

 

 

Thanks.

 
 
1 ACCEPTED SOLUTION
v-zhangti
Community Support
Community Support

Hi, @Easley06 

 

You can try the following methods.

Measure = 
VAR N1 =
    ABS ( [Today] - SELECTEDVALUE ( 'Table'[transaction date] ) )
VAR N2 =
    CALCULATE (
        COUNT ( 'Date'[Non working day] ),
        FILTER (
            ALL ( 'Date' ),
            [Date] >= SELECTEDVALUE ( 'Table'[transaction date] )
                && [Date] <= [Today]
                && [Non working day] = 1
        )
    )
RETURN
    N1 - N2

vzhangti_0-1661417685598.png

Is this the result you expect?

 

Best Regards,

Community Support Team _Charlotte

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

2 REPLIES 2
v-zhangti
Community Support
Community Support

Hi, @Easley06 

 

You can try the following methods.

Measure = 
VAR N1 =
    ABS ( [Today] - SELECTEDVALUE ( 'Table'[transaction date] ) )
VAR N2 =
    CALCULATE (
        COUNT ( 'Date'[Non working day] ),
        FILTER (
            ALL ( 'Date' ),
            [Date] >= SELECTEDVALUE ( 'Table'[transaction date] )
                && [Date] <= [Today]
                && [Non working day] = 1
        )
    )
RETURN
    N1 - N2

vzhangti_0-1661417685598.png

Is this the result you expect?

 

Best Regards,

Community Support Team _Charlotte

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

johnt75
Super User
Super User

You can try

Num working days =
NETWORKDAYS (
    SELECTEDVALUE ( 'Table'[transaction date] ),
    TODAY (),
    1,
    CALCULATETABLE ( VALUES ( 'Date'[Date] ), 'Date'[non_working_day] = 1 )
)

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