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ckolahi
Frequent Visitor

cumulative total with unique values

Hi guys

Here's the data set

 

ckolahi_0-1661976075961.png

 As you can see the last column is unique value.

I would like basically to have a cumulative sum by month (1st column) of this Payout_Monthly column

 Cumulative sum (Jan/Feb) = 1412,14+1412,14 = 2824 (YTD FEB)

 

any ideas

Thanks

1 ACCEPTED SOLUTION
v-yiruan-msft
Community Support
Community Support

Hi,@ ckolahi

According to your description, you want to deduplicate according to the [Month] field and find the sum of [Payout_Monthly]. Right?

Here are the steps you can follow:

(1)This is my test data:

yingyinr_0-1662363722446.png

 

(2) We can create a measure:  Cumulative sum

Cumulative sum =
SUMX (
    SUMMARIZE ( 'Test', 'Test'[Month], 'Test'[Payout_Monthly] ),
    [Payout_Monthly]
)

(3)Then we can test in the card and it can meet your need:

yingyinr_2-1662363822115.png

If this method does not meet your needs, you can provide us your sample data without sensitive data, or detailed input and output sample data, so that we can better help for you.

Best Regards

Community Support Team _ Rena
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

1 REPLY 1
v-yiruan-msft
Community Support
Community Support

Hi,@ ckolahi

According to your description, you want to deduplicate according to the [Month] field and find the sum of [Payout_Monthly]. Right?

Here are the steps you can follow:

(1)This is my test data:

yingyinr_0-1662363722446.png

 

(2) We can create a measure:  Cumulative sum

Cumulative sum =
SUMX (
    SUMMARIZE ( 'Test', 'Test'[Month], 'Test'[Payout_Monthly] ),
    [Payout_Monthly]
)

(3)Then we can test in the card and it can meet your need:

yingyinr_2-1662363822115.png

If this method does not meet your needs, you can provide us your sample data without sensitive data, or detailed input and output sample data, so that we can better help for you.

Best Regards

Community Support Team _ Rena
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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