Join us at FabCon Atlanta from March 16 - 20, 2026, for the ultimate Fabric, Power BI, AI and SQL community-led event. Save $200 with code FABCOMM.
Register now!Calling all Data Engineers! Fabric Data Engineer (Exam DP-700) live sessions are back! Starting October 16th. Sign up.
I have a table like this:
first | ans1 | second | ans2 | third | ans3 | max |
150 | yes | 170 | yes | 190 | no | 170 |
190 | yes | 190 | ||||
110 | no | 0 | ||||
130 | no | 110 | yes | 110 | ||
130 | yes | 190 | no | 170 | yes | 170 |
It's actually a Gabor-Granger analysis survey, stored like this, queue of columns, price, yes/no, second price, yes/no etc. I need to get max column, strugling couple days already, maybe someone could help? Max column take maximum price with according column ans with yes. The price range is 110-130-150-170-190
Solved! Go to Solution.
@Anonymous , A solution in Power Query, New custom column
let
_a = Table.Max(Table.SelectRows( Table.FromColumns({
{[first],[second],[third]},
{[ans1],[ans2],[ans3]}
}, {"Col1", "Col2"}), each [Col2] = "yes"), "Col1"),
_b= try Record.Field(_a, "Col1") otherwise 0
in
_b
Dax New Column
Column = Maxx(filter(union(row("Col1",[first],"Col2", [ans1]), row("Col1",[second],"Col2", [ans2]),row("Col1",[third],"Col2", [ans3])),[Col2]= "yes"),[Col1])+0
Here's another Power Query answer:
List.Max(
List.Transform(
{
{ [first], [ans1] },
{ [second], [ans2] },
{ [third], [ans3] }
},
each if List.Last(_) = "yes"
then List.First(_) else null // or 0 if you prefer
)
)
You can do nearly the same thing in DAX:
MAXX (
{
( [first], [ans1] ),
( [second], [ans2] ),
( [third], [ans3] )
},
IF ( [Value2] = "yes", [Value1], 0 )
)
@Anonymous , A solution in Power Query, New custom column
let
_a = Table.Max(Table.SelectRows( Table.FromColumns({
{[first],[second],[third]},
{[ans1],[ans2],[ans3]}
}, {"Col1", "Col2"}), each [Col2] = "yes"), "Col1"),
_b= try Record.Field(_a, "Col1") otherwise 0
in
_b
Dax New Column
Column = Maxx(filter(union(row("Col1",[first],"Col2", [ans1]), row("Col1",[second],"Col2", [ans2]),row("Col1",[third],"Col2", [ans3])),[Col2]= "yes"),[Col1])+0
Join the Fabric FabCon Global Hackathon—running virtually through Nov 3. Open to all skill levels. $10,000 in prizes!
Check out the October 2025 Power BI update to learn about new features.
User | Count |
---|---|
12 | |
11 | |
9 | |
8 | |
8 |