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FP68
Frequent Visitor

Syntax problem

Hello,

I've a clolumn with a long string [TAGS] in which I can find "ApplicationName=xxxxxx"
In this string, each data is separate with ";"
I just want to know the position of the ";" after the "ApplicationName=..."

Countries2 = 

var _x= SEARCH("ApplicationName",[TAGS],0,-1)

var _z= SEARCH(";",[TAGS],value(_x),blank())

RETURN _z

My column Countries2 is a Text data type and I've the message "An argument of function "SEARCH" has the wrong data type or has an invalid value"
Thanks a lot for your help

1 ACCEPTED SOLUTION
MasonMA
Super User
Super User

Hi, 

You may try

Countries2 =
VAR _x =
    SEARCH ( "ApplicationName=", [TAGS], 1, BLANK() )
VAR _z =
    _x + LEN ( "ApplicationName=" )
VAR _result=
    SEARCH ( ";", [TAGS], _z, BLANK() )
RETURN
    _result
 
Tested with some random data. 
MasonMA_2-1769436241966.png

 


 


 

View solution in original post

3 REPLIES 3
FP68
Frequent Visitor

Thanks a lot, it works fine

cengizhanarslan
Super User
Super User

Please try the measure below:

Countries2 =
VAR _x =
    SEARCH ( "ApplicationName=", [TAGS], 1, -1 )
VAR _z =
    IF (
        _x > 0,
        SEARCH ( ";", [TAGS], _x, BLANK() ),
        BLANK()
    )
RETURN
_z
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MasonMA
Super User
Super User

Hi, 

You may try

Countries2 =
VAR _x =
    SEARCH ( "ApplicationName=", [TAGS], 1, BLANK() )
VAR _z =
    _x + LEN ( "ApplicationName=" )
VAR _result=
    SEARCH ( ";", [TAGS], _z, BLANK() )
RETURN
    _result
 
Tested with some random data. 
MasonMA_2-1769436241966.png

 


 


 

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