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Sergei8000's avatar
Sergei8000
New Member
2 years ago
Solved

Splitting values where keys matching

I have two tables. In table 1 there is about 800 repeating key values. In table 100 unique key values and 20 columns with data values.

I want output where each matching value splitted by number of matches.

Table 1
id
A
B
A
C
A
A
C

 

Table 2   
unique_idCol1Col2Col3
A40010020
B200 800
C600800 

 

output   
idCol1Col2Col3
A100255
B200 800
A100255
C300400 
A100255
A100255
C300400 

 

How to achieve this?

  • hi, Sergei8000 

    try below

     

    Column 1= 
     var a = CALCULATE(SUM('Table 2'[Col1]))
     var b = CALCULATE(COUNT('Table 1'[id]))
      return
      DIVIDE(a,b)

     

    repeat for all column

  • Anonymous's avatar
    Anonymous
    2 years ago

    Hi Sergei8000 ,

     

    According to your description, here are my steps you can follow as a solution.

    (1) My test data is the same as yours.

    (2) We can create calculated columns.

    Col 1 = 
     var a = CALCULATE(SUM('Table 2'[Col1]),FILTER('Table 2','Table 2'[unique_id]=EARLIER('Table 1'[id])))
     var b = COUNTROWS(FILTER('Table 1','Table 1'[id]=EARLIER('Table 1'[id])))
      return
      DIVIDE(a,b)
    Col 2 = 
     var a = CALCULATE(SUM('Table 2'[Col2]),FILTER('Table 2','Table 2'[unique_id]=EARLIER('Table 1'[id])))
     var b = COUNTROWS(FILTER('Table 1','Table 1'[id]=EARLIER('Table 1'[id])))
      return
      DIVIDE(a,b)
    Col 3 = 
     var a = CALCULATE(SUM('Table 2'[Col3]),FILTER('Table 2','Table 2'[unique_id]=EARLIER('Table 1'[id])))
     var b = COUNTROWS(FILTER('Table 1','Table 1'[id]=EARLIER('Table 1'[id])))
      return
      DIVIDE(a,b)

    (3) Then the result is as follows.

    Best Regards,

    Neeko Tang

    If this post  helps, then please consider Accept it as the solution  to help the other members find it more quickly. 

2 Replies

  • Dangar332's avatar
    Dangar332
    Resident Rockstar

    hi, Sergei8000 

    try below

     

    Column 1= 
     var a = CALCULATE(SUM('Table 2'[Col1]))
     var b = CALCULATE(COUNT('Table 1'[id]))
      return
      DIVIDE(a,b)

     

    repeat for all column

  • Anonymous's avatar
    Anonymous
    Not applicable

    Hi Sergei8000 ,

     

    According to your description, here are my steps you can follow as a solution.

    (1) My test data is the same as yours.

    (2) We can create calculated columns.

    Col 1 = 
     var a = CALCULATE(SUM('Table 2'[Col1]),FILTER('Table 2','Table 2'[unique_id]=EARLIER('Table 1'[id])))
     var b = COUNTROWS(FILTER('Table 1','Table 1'[id]=EARLIER('Table 1'[id])))
      return
      DIVIDE(a,b)
    Col 2 = 
     var a = CALCULATE(SUM('Table 2'[Col2]),FILTER('Table 2','Table 2'[unique_id]=EARLIER('Table 1'[id])))
     var b = COUNTROWS(FILTER('Table 1','Table 1'[id]=EARLIER('Table 1'[id])))
      return
      DIVIDE(a,b)
    Col 3 = 
     var a = CALCULATE(SUM('Table 2'[Col3]),FILTER('Table 2','Table 2'[unique_id]=EARLIER('Table 1'[id])))
     var b = COUNTROWS(FILTER('Table 1','Table 1'[id]=EARLIER('Table 1'[id])))
      return
      DIVIDE(a,b)

    (3) Then the result is as follows.

    Best Regards,

    Neeko Tang

    If this post  helps, then please consider Accept it as the solution  to help the other members find it more quickly.