Forum Discussion

mahsy's avatar
mahsy
Helper I
4 years ago
Solved

Show duplicate rows

Hi !!   I want to display in the graphic the number of duplicate rows according to date. But i don't know how to count uniquely multiple columns.     Thank you for your help !    
duplicaterows
  • Anonymous's avatar
    Anonymous
    4 years ago

    Hi mahsy ，

     

    Please try this measure. And set the filters as shown in the figure.

    Measure = COUNTROWS('Table') - COUNTROWS(SUMMARIZE('Table','Table'[Course],'Table'[PR],'Table'[Date]))

    Attached PBIX file for reference.

    Best Regards,
    Gao
    Community Support Team

     

    If there is any post helps, then please consider Accept it as the solution to help the other members find it more quickly. If I misunderstand your needs or you still have problems on it, please feel free to let us know. Thanks a lot!

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Arul's avatar
Arul
Super User
4 years ago

mahsy ,

create a calculated column like the below and put that column in the X-axis (values) or Y-axis (values), then set the aggregation as count.

 

Earlier = COUNTX(filter(Table_count,EARLIER(Table_count[Course])=Table_count[Course] && EARLIER(Table_count[PR])=Table_count[PR] &&EARLIER(Table_count[Date])=Table_count[Date]),Table_count[Course])

 

Thanks,

Arul

 

mahsy's avatar
mahsy
Helper I
4 years ago

Thank you.

Unfortunately i'm in live  connection, so i can't create calculated column.

  • Arul's avatar
    Arul
    Super User
    4 years ago

    mahsy ,

    try this in measure,

    cal = CALCULATE(COUNT(Table_count[Course]),FILTER(ALL(Table_count),
COUNTX(filter(Table_count,
EARLIER(Table_count[Course])=Table_count[Course] && 
EARLIER(Table_count[PR])=Table_count[PR] &&
EARLIER(Table_count[Date])=Table_count[Date]),
Table_count[Course])))

    Thanks,

    Arul

    • mahsy's avatar
      mahsy
      Helper I
      4 years ago

      Here is what i get. It counts all rows. 

       

       

      I just want to count duplicate rows. Here is the expected result.

       

      thank you for your help !