Skip to main content
cancel
Showing results for 
Search instead for 
Did you mean: 

Find everything you need to get certified on Fabric—skills challenges, live sessions, exam prep, role guidance, and more. Get started

Reply
Anonymous
Not applicable

Row by Over Partion in Dax

Hello everyone,
I hope you have a splendid week.
I encountered the following question, and I hope you might help me here.
I tried to "convert" a query in SQL into dax, and I didn't manage to do so.
Here is the SQL query:

select 
ROW_NUMBER() OVER (PARTITION BY employee_id, customer_id ORDER BY Increament_copy_datetime desc) as row_num,
employee_id,
customer_id,
call_status,
Increament_copy_datetime
from tess_reports.fact_calls

The results I'm expecting to get are the one marked in yellow (The one with the highest rank, means the one with the rank of 1).

KatyaK_0-1640641122460.png

 

The idea here is to create a new table with the "yellow-marked" results as a variable (I plan to use this table with other filters and manipulations like so).
I'll appreciate your kind help!
Thanks!

2 ACCEPTED SOLUTIONS
wdx223_Daniel
Super User
Super User

NewTable=TOPN(1,SourceTable,RANKX(ALL(SourceTable[Increament_copy_datetime]),CALCULATE(MAX(SourceTable[Increament_copy_datetime]),ALLEXCEPT(SourceTable,SourceTable[employee_id],SourceTable[customer_id],SourceTable[Increament_copy_datetime])),,ASC))

View solution in original post

smpa01
Super User
Super User

@Anonymous  if you have a table like this

smpa01_0-1640662428981.png

 

The TSQL's ROW_NUMBER() equivalent would be following which you can achieve with a measure from the exisitng table wothout creating any more table

Row_Number = 
RANKX (
    FILTER (
        ALLSELECTED ( fact_calls ),
        fact_calls[customer_id] = MAX ( fact_calls[customer_id] ) --equivalent of PARTITION BY employee_id
            && fact_calls[employee_id] = MAX ( fact_calls[employee_id] )--, customer_id
    ),
    [_Increament_copy_datetime], -- equivalent of ORDER BY Increament_copy_datetime desc
    ,
    DESC
)

 

smpa01_1-1640662632770.png

 

 

 

Did I answer your question? Mark my post as a solution!
Proud to be a Super User!
My custom visualization projects
Plotting Live Sound: Viz1
Beautiful News:Viz1, Viz2, Viz3
Visual Capitalist: Working Hrs

View solution in original post

4 REPLIES 4
smpa01
Super User
Super User

@Anonymous  if you have a table like this

smpa01_0-1640662428981.png

 

The TSQL's ROW_NUMBER() equivalent would be following which you can achieve with a measure from the exisitng table wothout creating any more table

Row_Number = 
RANKX (
    FILTER (
        ALLSELECTED ( fact_calls ),
        fact_calls[customer_id] = MAX ( fact_calls[customer_id] ) --equivalent of PARTITION BY employee_id
            && fact_calls[employee_id] = MAX ( fact_calls[employee_id] )--, customer_id
    ),
    [_Increament_copy_datetime], -- equivalent of ORDER BY Increament_copy_datetime desc
    ,
    DESC
)

 

smpa01_1-1640662632770.png

 

 

 

Did I answer your question? Mark my post as a solution!
Proud to be a Super User!
My custom visualization projects
Plotting Live Sound: Viz1
Beautiful News:Viz1, Viz2, Viz3
Visual Capitalist: Working Hrs
Anonymous
Not applicable

Thank you too! 

Your method works for me as well!!

appreciate the help:))

wdx223_Daniel
Super User
Super User

NewTable=TOPN(1,SourceTable,RANKX(ALL(SourceTable[Increament_copy_datetime]),CALCULATE(MAX(SourceTable[Increament_copy_datetime]),ALLEXCEPT(SourceTable,SourceTable[employee_id],SourceTable[customer_id],SourceTable[Increament_copy_datetime])),,ASC))

Anonymous
Not applicable

Thank you!!
It worked I appreciate your help :)))

Helpful resources

Announcements
Sept PBI Carousel

Power BI Monthly Update - September 2024

Check out the September 2024 Power BI update to learn about new features.

September Hackathon Carousel

Microsoft Fabric & AI Learning Hackathon

Learn from experts, get hands-on experience, and win awesome prizes.

Sept NL Carousel

Fabric Community Update - September 2024

Find out what's new and trending in the Fabric Community.