Skip to main content
Showing results for 
Search instead for 
Did you mean: 

Find everything you need to get certified on Fabric—skills challenges, live sessions, exam prep, role guidance, and more. Get started

Frequent Visitor

Return multiple values from lookup

Does anyone know if there is a way to lookup a value in a table and return multiple values split by comma in another column?


Resolver III
Resolver III


if there is no relationship between two tables you should do it on this way:


tbl imagetbl image




View solution in original post

Resolver III
Resolver III

You're welcome. It seems that a conditional statement is not defined in your Filter() function and only the field name has been mentioned.

With conditionWith condition


Without conditionWithout condition

Thank you again for your help, this is now what i have 
Column = CONCATENATEX(FILTER(Issues,Issues[IssueLinks.LINKED_ISSUE_KEY]=Issues[IssueLinks.LINKED_ISSUE_KEY] ,Issues[Organizations_14102.Organizations],",")

what i am trying to do is bring back multiple Organizations against the linked issue key so like using lookupvalue to bring back multiple values split by a comma in one column.

Second parameter of Filter() function is not correct, I see both side of the equal sign are the same.


@baghdadi62  i now haver this 

Column = CONCATENATEX(FILTER(Issues,Issues[ISSUE_ID] = Issues[IssueLinks.LINKED_ISSUE_ID]),Issues[Organizations_14102.Organizations])
this now is bringing back only blanks, what im trying to achieve is against each linked issue id there will be multiple Organizations_14102.Organizations so i need a similar function to lookupvalue but to bring back multiple values in one column split by a comma so using something a bit like this 
LOOKUPVALUE(Issues[Organizations_14102.Organizations],Issues[ISSUE_KEY],Issues[IssueLinks.LINKED_ISSUE_KEY]) but to bring back multiple results.

It seems that both side of the equal sign are columns of one table that not correct.

Resolver III
Resolver III


if there is no relationship between two tables you should do it on this way:


tbl imagetbl image




Hi @baghdadi62 thank you for your reply, this is what i have 

Column = CONCATENATEX(FILTER(Issues,Issues[IssueLinks.LINKED_ISSUE_KEY]),Issues[Organizations_14102.Organizations],",")
Its now telling me i cant convert the value to true or false, any ideas? both columns are in the same data set but it should be returning many Organizations against a linked key but it doesnt seem to be working, any ideas?
thank you again for your help

Helpful resources


Europe’s largest Microsoft Fabric Community Conference

Join the community in Stockholm for expert Microsoft Fabric learning including a very exciting keynote from Arun Ulag, Corporate Vice President, Azure Data.

Power BI Carousel June 2024

Power BI Monthly Update - June 2024

Check out the June 2024 Power BI update to learn about new features.


Fabric Community Update - June 2024

Get the latest Fabric updates from Build 2024, key Skills Challenge voucher deadlines, top blogs, forum posts, and product ideas.

RTI Forums Carousel3

New forum boards available in Real-Time Intelligence.

Ask questions in Eventhouse and KQL, Eventstream, and Reflex.