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Anonymous's avatar
Anonymous
Not applicable
6 years ago
Solved

Refering to Variable Column - Simple Case

Hello My Friends,

 

How Are You?

 

So I Have a Table Like this:

 

 

Travel IDMotiveValue
1A1000
2A2000
1B1000
1C2000
2B

1000

3A3000
4A2000
4B1000

 

 

So, what i need is to take All Travels IDs wich has the same number and SUM it!

 

If the Sum's Value is between 0 and 1000 Show it as Low Cost

If the Sum's Value is Over 1001 Show it as High Cost

 

After that I Wanna count how many Low Cost, How Many High Cost Travels i have

 

Is it possible to do this without creating a New Table? Just creating a New Measure?

 

I Was trying to create a new measure, than summarize my table and finally do an "If", but i can not refer to my Variables Columns using "IF"

 

Awnser =

VAR MyVar = Summarize('Table'; 'Table'[Travel ID]; "TOTAL"; Sum('Table'[Travel ID]))

RETURN

If ( MyVar[TOTAL] < 1001 ; "Low Cost"; "High Cost)

 

 

  • Hi Anonymous ,

     

    First create a table with your ranges:

     

    After create this measure:

    Measure =
    VAR _tb = ADDCOLUMNS(SUMMARIZE('Table'; 'Table'[Travel ID]; "Total"; SUM('Table'[Value])); "RangeDesc";
    SELECTCOLUMNS(FILTER(tb_range; [Total] >= tb_range[Min] && [Total] <= tb_range[Max]); "RangeDesc"; tb_range[DescriptionRange]))
    RETURN COUNTX(_tb; [RangeDesc])
     
     
    I've inputed another value, less than 1000 to try the results.
     
    Did I answer your question? Mark my post as a solution!
    Ricardo
     

     

     

1 Reply

  • camargos88's avatar
    camargos88
    Community Champion

    Hi Anonymous ,

     

    First create a table with your ranges:

     

    After create this measure:

    Measure =
    VAR _tb = ADDCOLUMNS(SUMMARIZE('Table'; 'Table'[Travel ID]; "Total"; SUM('Table'[Value])); "RangeDesc";
    SELECTCOLUMNS(FILTER(tb_range; [Total] >= tb_range[Min] && [Total] <= tb_range[Max]); "RangeDesc"; tb_range[DescriptionRange]))
    RETURN COUNTX(_tb; [RangeDesc])
     
     
    I've inputed another value, less than 1000 to try the results.
     
    Did I answer your question? Mark my post as a solution!
    Ricardo