Skip to main content
cancel
Showing results for 
Search instead for 
Did you mean: 

Don't miss out! 2025 Microsoft Fabric Community Conference, March 31 - April 2, Las Vegas, Nevada. Use code MSCUST for a $150 discount. Prices go up February 11th. Register now.

Reply
Yiyi
Helper I
Helper I

How to create a rank column with only distinct numbers? +RAND() is not working.

Hello kind friends :), 

 

Could you please have a look at my DAX code below? I am creating a table which calculates the distinct count for each media sources and I also trying to add a column of ranks for the purpose of calculating running total later. I need  distinct numbers for my ranks otherwise the running total won't work. In order to achieve this goal, I used +rand() to avoid ranks with same values, but the result looks pretty weird. Do you know why? Thanks a lot! 

 

Table = VAR _t= SUMMARIZE(
            ALLSELECTED('Main Data'),
            'Main Data'[Media],
            "Unique_Item_Count", DISTINCTCOUNT('Main Data'[HeadlineID])
        )
RETURN 
ADDCOLUMNS(
    _t,
    "Rank",
    RANKX(_t,[Unique_Item_Count]+RAND(),,DESC,Dense)  
)

 Result: 

Yiyi_0-1690916752704.png

 

1 ACCEPTED SOLUTION
OwenAuger
Super User
Super User

Hello @Yiyi 

Using RANX with RAND() in this way is not reliable.

 

RANKX works by determining the position of the current value "within" the list of values computed for each row of the table.

Using your existing expression, RAND() will be added to both the "current" value and the values per row of the table independently, which will inevitably result in ranks that occur between the values corresponding to rows of the table.

 

I would instead suggest using RANK, which can use the Media column to break ties.

Change the RANKX expression to:

RANK (
    DENSE,
    _t,
    ORDERBY ( [Unique_Item_Count], DESC, 'Main Data'[Media], ASC ),
    DEFAULT
)

Does this work for you?

 

Regards


Owen Auger
Did I answer your question? Mark my post as a solution!
Blog
Twitter
LinkedIn

View solution in original post

2 REPLIES 2
OwenAuger
Super User
Super User

Hello @Yiyi 

Using RANX with RAND() in this way is not reliable.

 

RANKX works by determining the position of the current value "within" the list of values computed for each row of the table.

Using your existing expression, RAND() will be added to both the "current" value and the values per row of the table independently, which will inevitably result in ranks that occur between the values corresponding to rows of the table.

 

I would instead suggest using RANK, which can use the Media column to break ties.

Change the RANKX expression to:

RANK (
    DENSE,
    _t,
    ORDERBY ( [Unique_Item_Count], DESC, 'Main Data'[Media], ASC ),
    DEFAULT
)

Does this work for you?

 

Regards


Owen Auger
Did I answer your question? Mark my post as a solution!
Blog
Twitter
LinkedIn

It works perfectly. Thanks so much for your time 😊

Helpful resources

Announcements
Las Vegas 2025

Join us at the Microsoft Fabric Community Conference

March 31 - April 2, 2025, in Las Vegas, Nevada. Use code MSCUST for a $150 discount!

Jan25PBI_Carousel

Power BI Monthly Update - January 2025

Check out the January 2025 Power BI update to learn about new features in Reporting, Modeling, and Data Connectivity.

December 2024

A Year in Review - December 2024

Find out what content was popular in the Fabric community during 2024.