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freginier
Solution Specialist
Solution Specialist

Get Previous year from selected year

Hello, 

 

Need help please ! 

I need to get value of previous year depend year select with a slicer. 

 

When I select 2021 I want to see value for 2020. how can I do that ?

I try to use SELECTEDVALUE : CALCULATE(sum(value), YEAR(date)=SELECTEDVALUE(Col1)-1)... 

 

Thank You

 

freginier_0-1634931349552.png

 

 

2 ACCEPTED SOLUTIONS

Thank you ! that work with a Date not connected (I create a Date Table not connected).

Any solution with a connected Date ? 

View solution in original post

Hi, @freginier 

As far as I’m concerned, you can just use one single table without a calendar table connected to achieve your requirement, you can create a measure like this:

Sum = CALCULATE(SUM('Table'[Amount]),FILTER(ALL('Table'),[Year]=SELECTEDVALUE('Table'[Year])-1))

Then you can create a card chart to place the measure like this:

vrobertqmsft_0-1635759757124.png

 

And you can get what you want.

 

Thank you very much!

 

Best Regards,

Community Support Team _Robert Qin

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

3 REPLIES 3
Greg_Deckler
Super User
Super User

@freginier Try:

CALCULATE(sum(value), ALL('Table'), YEAR(date)=SELECTEDVALUE(Col1)-1)

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DAX is easy, CALCULATE makes DAX hard...

Thank you ! that work with a Date not connected (I create a Date Table not connected).

Any solution with a connected Date ? 

Hi, @freginier 

As far as I’m concerned, you can just use one single table without a calendar table connected to achieve your requirement, you can create a measure like this:

Sum = CALCULATE(SUM('Table'[Amount]),FILTER(ALL('Table'),[Year]=SELECTEDVALUE('Table'[Year])-1))

Then you can create a card chart to place the measure like this:

vrobertqmsft_0-1635759757124.png

 

And you can get what you want.

 

Thank you very much!

 

Best Regards,

Community Support Team _Robert Qin

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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