Forum Discussion
Anonymous
3 years agoNot applicable
Finding identifier whose given value is smallest
Hello
I need your help for a simple issue I cannot solve... I have a table, named TBL below, that contains columns PR, FA and Prio. I need to create a new column RPR with content equivalent to ExpectedPR column below. It gives for set of PR with same FA the one which has lowest Prio
RPR1 below is giving in front of PR the Priority but what I need is PR id whose value is lowest
RPR1 = CALCULATE(
MIN([Prio]),
FILTER(TBL,TBL[FA]=EARLIEST([FA]))
)
I tried several trials using TOPN, FIRSTNONBLANK, CALCULATE, SUMMARIZE,... but I am not able to find the correct formula. Any idea?
Below just to load the example
let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WCjBU0lFycwSRRkAcYKQUqxMNomCihkiixlhFTcCiIB0g+QBTiKgpXNQIKhoLAA==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [PR = _t, FA = _t, Prio = _t, ExpectedPR = _t])
in
Source
Thanks for your help!
You can use
Calc PR = VAR MinPriority = CALCULATE( MIN( 'Query1'[Prio]), ALLEXCEPT(Query1, Query1[FA]) ) VAR Result = CALCULATE( MIN( 'Query1'[PR]), ALLEXCEPT(Query1, Query1[FA]), 'Query1'[Prio] = MinPriority) RETURN Result
2 Replies
- johnt75Super User
You can use
Calc PR = VAR MinPriority = CALCULATE( MIN( 'Query1'[Prio]), ALLEXCEPT(Query1, Query1[FA]) ) VAR Result = CALCULATE( MIN( 'Query1'[PR]), ALLEXCEPT(Query1, Query1[FA]), 'Query1'[Prio] = MinPriority) RETURN Result - AnonymousNot applicable
Thanks a lot johnt75, you made my day 😊