Power BI is turning 10! Tune in for a special live episode on July 24 with behind-the-scenes stories, product evolution highlights, and a sneak peek at what’s in store for the future.
Save the dateEnhance your career with this limited time 50% discount on Fabric and Power BI exams. Ends August 31st. Request your voucher.
How to extract out of “Column Description” the alphanumeric ID that always starts with the letter P and is followed by 7 digits and put it in a separate column?
Column Description |
Charles has engaged on Project P5671223 with Peter |
with P8702345 the delivery succeeds to saint Paul and Mary |
together with others P9906123 was a success |
William and John knew about P8765439 |
Paul and Peter as well as Anne like the breeze P9908765 brings |
Solved! Go to Solution.
I couldn't do it with DAX, but if M code is okay then
= Text.Middle(Text.Select([Column Description], {"0".."9"}), Text.PositionOf(Text.Select([Column Description], {"P", "0".."9"}), "P")
New Column =
VAR _Description = Table[Column Description]
VAR _Pattern = "P\d{7}"
VAR _Match = REGEXMATCH(Table[Column Description], "P\d{7}")
VAR _ExtractedID = IF(_Match, REGEXEXTRACT(_Description, _Pattern), BLANK())
RETURN _ExtractedID
Thx for this proposal - took me a second to find out that this is R 🙂
I couldn't do it with DAX, but if M code is okay then
= Text.Middle(Text.Select([Column Description], {"0".."9"}), Text.PositionOf(Text.Select([Column Description], {"P", "0".."9"}), "P")
nice - quick & easy done.
Check out the July 2025 Power BI update to learn about new features.
This is your chance to engage directly with the engineering team behind Fabric and Power BI. Share your experiences and shape the future.
User | Count |
---|---|
23 | |
10 | |
10 | |
9 | |
7 |