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Hi everybody,
this is my first post.
please help me,
i would like to distinct count vendorNo, with leadtime filter
here is my table
year, vendorNo, Account, Leadtime
2020 | 0007000995 | 7570004000 | 1 |
2020 | 0003000871 | 7520002000 | 1 |
2020 | 0007000316 | 7570003000 | 1 |
2020 | 0007000316 | 7520002001 | 1.5 |
2020 | 0003002554 | 7410009000 | 2 |
2020 | 0003000871 | 7520004001 | 2 |
2020 | 0003002554 | 7570001000 | 2.33333333333333 |
2020 | 0003000871 | 7570003000 | 2.35593220338983 |
2020 | 0003002554 | 7520001000 | 2.5 |
and here is my DAX :
Solved! Go to Solution.
Hi, @Kagechiyo
Please correct me if I am wrong.
I think the result should be 3.
I am not sure about how you wrote your AVGLT measure, but please kindly check the below measure if it is suitable for you.
DAXcountofVendor =
VAR removeGL =
FILTER (
SUMMARIZE (
'average lead time',
'average lead time'[vendor_No],
"avglt", AVERAGEX ( 'average lead time', 'average lead time'[Leadtime] )
),
[avglt] > 0
&& [avglt] <= 2
)
RETURN
COUNTROWS ( removeGL )
Hi, My name is Jihwan Kim.
If this post helps, then please consider accept it as the solution to help other members find it faster.
If this post helps, then please consider accepting it as the solution to help other members find it faster, and give a big thumbs up.
Schedule a short Teams meeting to discuss your question
Hi, @Kagechiyo
Please correct me if I am wrong.
I think the result should be 3.
I am not sure about how you wrote your AVGLT measure, but please kindly check the below measure if it is suitable for you.
DAXcountofVendor =
VAR removeGL =
FILTER (
SUMMARIZE (
'average lead time',
'average lead time'[vendor_No],
"avglt", AVERAGEX ( 'average lead time', 'average lead time'[Leadtime] )
),
[avglt] > 0
&& [avglt] <= 2
)
RETURN
COUNTROWS ( removeGL )
Hi, My name is Jihwan Kim.
If this post helps, then please consider accept it as the solution to help other members find it faster.
If this post helps, then please consider accepting it as the solution to help other members find it faster, and give a big thumbs up.
Schedule a short Teams meeting to discuss your question
thank you, @Jihwan_Kim
after some modification i manage to get what i want..
but i understand that there is another way to count the distinct.
is by grouping.
thanx=]
2020 | ;0007000995 | ;7570004000 | ;1 |
2020 | ;0003003612 | ;7520002000 | ;1 |
2020 | ;0003003638 | ;7570003000 | ;1 |
2020 | ;0007000316 | ;7520002001 | ;1.5 |
2020 | ;0003002480 | ;7410009000 | ;2 |
2020 | ;0003000871 | ;7520004001 | ;2 |
2020 | ;0003002554 | ;7570001000 | ;2.33333333333333 |
2020 | ;0003000871 | ;7570003000 | ;2.35593220338983 |
2020 | ;0003002554 | ;7520001000 | ;2.5 |
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