Forum Discussion
Distinctcount by excluding column
Hi everybody,
this is my first post.
please help me,
i would like to distinct count vendorNo, with leadtime filter
here is my table
year, vendorNo, Account, Leadtime
| 2020 | 0007000995 | 7570004000 | 1 |
| 2020 | 0003000871 | 7520002000 | 1 |
| 2020 | 0007000316 | 7570003000 | 1 |
| 2020 | 0007000316 | 7520002001 | 1.5 |
| 2020 | 0003002554 | 7410009000 | 2 |
| 2020 | 0003000871 | 7520004001 | 2 |
| 2020 | 0003002554 | 7570001000 | 2.33333333333333 |
| 2020 | 0003000871 | 7570003000 | 2.35593220338983 |
| 2020 | 0003002554 | 7520001000 | 2.5 |
and here is my DAX :
Hi, Kagechiyo
Please correct me if I am wrong.
I think the result should be 3.
I am not sure about how you wrote your AVGLT measure, but please kindly check the below measure if it is suitable for you.
DAXcountofVendor =
VAR removeGL =
FILTER (
SUMMARIZE (
'average lead time',
'average lead time'[vendor_No],
"avglt", AVERAGEX ( 'average lead time', 'average lead time'[Leadtime] )
),
[avglt] > 0
&& [avglt] <= 2
)
RETURN
COUNTROWS ( removeGL )Hi, My name is Jihwan Kim.
If this post helps, then please consider accept it as the solution to help other members find it faster.
3 Replies
- KagechiyoNew Member
2020 ;0007000995 ;7570004000 ;1 2020 ;0003003612 ;7520002000 ;1 2020 ;0003003638 ;7570003000 ;1 2020 ;0007000316 ;7520002001 ;1.5 2020 ;0003002480 ;7410009000 ;2 2020 ;0003000871 ;7520004001 ;2 2020 ;0003002554 ;7570001000 ;2.33333333333333 2020 ;0003000871 ;7570003000 ;2.35593220338983 2020 ;0003002554 ;7520001000 ;2.5 - Jihwan_KimSuper User
Hi, Kagechiyo
Please correct me if I am wrong.
I think the result should be 3.
I am not sure about how you wrote your AVGLT measure, but please kindly check the below measure if it is suitable for you.
DAXcountofVendor =
VAR removeGL =
FILTER (
SUMMARIZE (
'average lead time',
'average lead time'[vendor_No],
"avglt", AVERAGEX ( 'average lead time', 'average lead time'[Leadtime] )
),
[avglt] > 0
&& [avglt] <= 2
)
RETURN
COUNTROWS ( removeGL )Hi, My name is Jihwan Kim.
If this post helps, then please consider accept it as the solution to help other members find it faster.
- KagechiyoNew Member
thank you, Jihwan_Kim
after some modification i manage to get what i want..but i understand that there is another way to count the distinct.
is by grouping.
thanx=]