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Allisond
Advocate II
Advocate II

Distinct Count of ID's associated with a given date from rows with start and end dates.

Hello!

 

I am trying to get a distinct count of ID's noted within a specific date range.  My table has columns with ID's, start and end dates.

 

I can get the total rows that fall within the date range on any given day from the following:

 

AL Apt Census =
VAR StartDate = VALUE(SELECTEDVALUE( 'Assisted Living MXC Census'[MOVEINDATE] ) )
VAR EndDate = VALUE(SELECTEDVALUE( 'Assisted Living MXC Census'[ENDDATE] ) )
VAR MinDate = VALUE( MIN( Dates[DayDate] ) )
VAR MaxDate = VALUE( MAX( Dates[DayDate] ) )
VAR CensusPrimary = SWITCH(TRUE(),
SELECTEDVALUE('Assisted Living MXC Census'[PAYORTYPENAME]) = "Primary" || SELECTEDVALUE('Assisted Living MXC Census'[PAYORTYPENAME]) = "Couple",
IF( AND( StartDate <= MinDate, EndDate >= MinDate ) ,
MIN(EndDate, MaxDate ) - MinDate +1,
IF( AND( AND( StartDate >= MinDate, StartDate <= MaxDate), EndDate >= MinDate),
MIN( EndDate, MaxDate) - StartDate +1,
BLANK()) ),BLANK())
RETURN
CensusPrimary
 
Is there anyway to get a distinct count of a value noted on any given day?  I need the distinct count of the ID's assocated with this census number.  I am stuck.
 
Thank you for any help!
1 ACCEPTED SOLUTION
v-robertq-msft
Community Support
Community Support

Hi, 

According to your description, I can roughly understand your requirement, you want to get a distinct count of ID's noted within a specific date range, right? I think you can try this method to get the expected result:

This is the test data I created based on your description:

vrobertqmsft_0-1641278563620.png

 

You can create a calendar table to be placed into the slicer:

Calendar = CALENDAR(DATE(2022,1,1),DATE(2022,1,5))

 

Then you can create a measure like this:

Distinct count =

var _start=MINX(ALLSELECTED('Calendar'),'Calendar'[Date])

var _end=MAXX(ALLSELECTED('Calendar'),'Calendar'[Date])

return

CALCULATE(DISTINCTCOUNT('Table'[ID]),FILTER(ALL('Table'),[Start Date]>=_start&&[End Date]<=_end))

 

 

And you can create a slicer and a card chart to get what you want, like this:

vrobertqmsft_1-1641278563625.png

 

You can download my test pbix file below

 

If this result is not what you want, you can post some sample data(without sensitive data) and your expected result.

How to Get Your Question Answered Quickly 

Thank you very much!

 

Best Regards,

Community Support Team _Robert Qin

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

2 REPLIES 2
v-robertq-msft
Community Support
Community Support

Hi, 

According to your description, I can roughly understand your requirement, you want to get a distinct count of ID's noted within a specific date range, right? I think you can try this method to get the expected result:

This is the test data I created based on your description:

vrobertqmsft_0-1641278563620.png

 

You can create a calendar table to be placed into the slicer:

Calendar = CALENDAR(DATE(2022,1,1),DATE(2022,1,5))

 

Then you can create a measure like this:

Distinct count =

var _start=MINX(ALLSELECTED('Calendar'),'Calendar'[Date])

var _end=MAXX(ALLSELECTED('Calendar'),'Calendar'[Date])

return

CALCULATE(DISTINCTCOUNT('Table'[ID]),FILTER(ALL('Table'),[Start Date]>=_start&&[End Date]<=_end))

 

 

And you can create a slicer and a card chart to get what you want, like this:

vrobertqmsft_1-1641278563625.png

 

You can download my test pbix file below

 

If this result is not what you want, you can post some sample data(without sensitive data) and your expected result.

How to Get Your Question Answered Quickly 

Thank you very much!

 

Best Regards,

Community Support Team _Robert Qin

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

bcdobbs
Super User
Super User

I think you might be making life hard for yourself with the nested SWITCH/If when you could be using CALCULATE.

 

Are you able to share a demo pbix? Fairly sure we should be able to help.


Ben



Ben Dobbs

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