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GiTchitchinadze
Frequent Visitor

Damage percentage over Yearly total of sales

I work for insurance company and we have agroinsurance as part of portfolio.  My task is to identify damage percentage of claims in months and subcategories like villages etc. I made a measure (claims/profit) and it does the job in yearly overview but when I choose august for example, I want august claims to be divided by all years profit, but it cuts profit to august aswell and the result I'm getting is august claims divided by august profit and thats not what I want. What I want is that whatever month I choose it has to be divided by that years total profit.

1 ACCEPTED SOLUTION
v-yangliu-msft
Community Support
Community Support

Hi  @GiTchitchinadze ,

I created some data:

vyangliumsft_0-1655109327551.png

Here are the steps you can follow:

1. Create measure.

Measure =
var _selectyear=SELECTEDVALUE('Table'[Date].[Year])
var _selectmonth=SELECTEDVALUE('Table'[Date].[Month])
var _claims=CALCULATE(SUM('Table'[claims]),FILTER(ALL('Table'),'Table'[Date].[Year]=_selectyear&&'Table'[Date].[Month]=_selectmonth))
var _profit=CALCULATE(SUM('Table'[profit]),FILTER(ALL('Table'),'Table'[Date].[Year]=_selectyear))
return
DIVIDE(_claims,_profit)

2. Result:

vyangliumsft_1-1655109327554.png

 

Best Regards,

Liu Yang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly

View solution in original post

1 REPLY 1
v-yangliu-msft
Community Support
Community Support

Hi  @GiTchitchinadze ,

I created some data:

vyangliumsft_0-1655109327551.png

Here are the steps you can follow:

1. Create measure.

Measure =
var _selectyear=SELECTEDVALUE('Table'[Date].[Year])
var _selectmonth=SELECTEDVALUE('Table'[Date].[Month])
var _claims=CALCULATE(SUM('Table'[claims]),FILTER(ALL('Table'),'Table'[Date].[Year]=_selectyear&&'Table'[Date].[Month]=_selectmonth))
var _profit=CALCULATE(SUM('Table'[profit]),FILTER(ALL('Table'),'Table'[Date].[Year]=_selectyear))
return
DIVIDE(_claims,_profit)

2. Result:

vyangliumsft_1-1655109327554.png

 

Best Regards,

Liu Yang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly

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