Skip to main content
cancel
Showing results for 
Search instead for 
Did you mean: 

Register now to learn Fabric in free live sessions led by the best Microsoft experts. From Apr 16 to May 9, in English and Spanish.

Reply
ausafonly
Regular Visitor

DAX query to return CompI have liant or Non Compliant based on the filter

ausafonly_0-1684672982571.png

Based on this data I want to create a calculated column or measure.

If compliance_status is both installed and required result should be Non compliant otherwise compliant in a new column.

I have no idea how to achieve it tried multiple ways but no luck.

Any suggestion how to achieve it.

3 REPLIES 3
Mrxiang
Helper II
Helper II

You can use the DAX language to create a computed column or metric to implement your requirements. Here is a sample DAX formula:

Compliance Status = IF(Table1[Compliance_Status] = "Installed" && Table1[Compliance_Status] = "Required",  "Non compliant", "Compliant")

This formula checks whether the value in the Compliance_Status column contains both "Installed" and "Required". If so, the result is "Non compliant", otherwise it is "Compliant". You can apply this formula to a new computed column or measure to display the results in a table.
v-shex-msft
Community Support
Community Support

Hi @ausafonly,

You can try to use the following measure formula to get the correspond statues count based on current hostname:

formula =
VAR currName =
    SELECTEDVALUE ( Table[HostName] )
VAR summary =
    SUMMARIZE (
        FILTER (
            ALLSELECTED ( Table ),
            [compliance_status] IN { "Installed", "Required" }
        ),
        [HostName],
        [compliance_status]
    )
RETURN
    IF (
        COUNTROWS ( FILTER ( summary, [HostName] = currName ) ) < 2,
        "Compliant",
        "Non compliant"
    )

Regards,

Xiaoxin Sheng

Community Support Team _ Xiaoxin
If this post helps, please consider accept as solution to help other members find it more quickly.

Unfortunately it didn't worked as expected.

However I tried another method and it worked.

I have created a duplicate table and then used group by to achieve the solution.

Helpful resources

Announcements
Microsoft Fabric Learn Together

Microsoft Fabric Learn Together

Covering the world! 9:00-10:30 AM Sydney, 4:00-5:30 PM CET (Paris/Berlin), 7:00-8:30 PM Mexico City

PBI_APRIL_CAROUSEL1

Power BI Monthly Update - April 2024

Check out the April 2024 Power BI update to learn about new features.

April Fabric Community Update

Fabric Community Update - April 2024

Find out what's new and trending in the Fabric Community.

Top Solution Authors