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Hi All!
I have a challenge, I would like to display a counter value in table visual, which should return an increasing number (increment +1) depending on the displayed and filtered items shown in the table visual.
I have a calculated table, which contains invoices' data.
| ID | Partner | Category - Main | Category - Sub |
| AX1 | A | A | A |
| AV6 | B | A | B |
| ZT1 | C | A | C |
| DS2 | D | B | A |
| AS7 | D | B | B |
If I put all data fields from the above shown table into a table visualization, I would like to add a measure which returns an index or counter value based on how the table is filtered. What I want to achieve.
Example 1.:
If I filter the table for category - main = 'A' then I would need the following result in the table visualization
| ID | Partner | Category - Main | Category - Sub | MEASURE - Index |
| AX1 | A | A | A | 1 |
| AV6 | B | A | B | 2 |
| ZT1 | C | A | C | 3 |
Example 2.:
If I filter the table for category - main = 'B' then I would need the following result in the table visualization
| ID | Partner | Category - Main | Category - Sub | MEASURE - Index |
| DS2 | D | B | A | 1 |
| AS7 | D | B | B | 2 |
Do you have any solution on this issue?
Thanks a lot!
David
Solved! Go to Solution.
Hi @freidav1984 ,
I suggest you to try this code to create a measure.
Dynamic Index =
VAR _1 =
ADDCOLUMNS (
ALLSELECTED ( 'Table' ),
"Merage", COMBINEVALUES ( " ", [Category - Main], [Category - Sub] )
)
VAR _2 =
ADDCOLUMNS ( _1, "Index", RANKX ( _1, [Merage],, ASC, DENSE ) )
RETURN
SUMX ( FILTER ( _2, [ID] = MAX ( 'Table'[ID] ) ), [Index] )
Result is as below.
Best Regards,
Rico Zhou
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @freidav1984 ,
I suggest you to try this code to create a measure.
Dynamic Index =
VAR _1 =
ADDCOLUMNS (
ALLSELECTED ( 'Table' ),
"Merage", COMBINEVALUES ( " ", [Category - Main], [Category - Sub] )
)
VAR _2 =
ADDCOLUMNS ( _1, "Index", RANKX ( _1, [Merage],, ASC, DENSE ) )
RETURN
SUMX ( FILTER ( _2, [ID] = MAX ( 'Table'[ID] ) ), [Index] )
Result is as below.
Best Regards,
Rico Zhou
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
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